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2 years ago

Please help ASAP I’m really dumb, I’ll give u 5 stars, thank u, and make u brainliest ToT

Mathematics

1 answer:

Lina20 [59]2 years ago

3 0

Usually I just use slope calculator hope that helps

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PLEASE HELP 30 POINTS Wendell is looking over some data regarding the strength, measured in Pascals (Pa), of some building mater

jarptica [38.1K]

Logarithmic functions and exponential functions are inverse and opposite of one another

The logarithmic function is $y = \log_2(x)$ , and the length at 8 pascals is 3 units

<h3>How to determine the logarithmic function</h3>

The exponential function is given as:

$f(x) = 2^x$

Express f(x) as y

$y = 2^x$

Swap the positions of x and y

$x = 2^y$

Take the logarithm of both sides

$\log(x) = \log(2^y)$

Apply the rule of logarithm

$\log(x) = y\log(2)$

Divide both sides by log(2)

$y = \frac{\log(x)}{\log(2)}$

Apply the change of base rule of logarithm

$y = \log_2(x)$

When the strength is 8 pascals, we have:

$y = \log_2(8)$

Express 8 as 2^3

$y = \log_2(2^3)$

So, we have:

$y =3 \log_2(2)$

Evaluate log 2 base 2

$y =3$

Hence, the logarithmic function is $y = \log_2(x)$ , and the length at 8 pascals is 3 units

Read more about logarithmic and exponential functions at:

brainly.com/question/11464095

7 0

2 years ago

What is the surface area of a cylinder with a diameter of 8 and a height of 18?Express the answer in terms of pi

viktelen [127]

Step-by-step explanation:

diameter: 8

radius: 4

height: 18

$A=2\pi rh+2\pi r^2\\A=2\pi(4)(18)+2\pi(4)^2\\A=2\pi(72)+2\pi(16)\\A=144\pi+32\pi\\A=176\pi$

4 0

3 years ago

Please please use explanation with answer

KIM [24]

Answer:

$\large\boxed{\theta=-\dfrac{\pi}{4}+k\pi\ or\ \theta=k\pi}\ for\ k\in\mathbb{Z}$

Step-by-step explanation:

$\tan^2\theta+\tan\theta=0\\\\\tan\theta(\tan\theta+1)=0\iff\tan\theta=0\ \vee\ \tan\theta+1=0\\\\\tan\theta=0\Rightarrow \theta=k\pi\ \text{for}\ k\in\mathbb{Z}\\\\\tan\theta+1=0\qquad\text{subtract 1 from both sides}\\\\\tan\theta=-1\Rightarrow\theta=-\dfrac{\pi}{4}+k\pi\ \text{for}\ k\in\mathbb{Z}$