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viva [34]
3 years ago
15

Let a= x2 +4 rewrite the following equation in terms of a and set it equal to zero. (X2 + 4)2 + 32 = 12x2 + 48 in the resulting

equation what is the coefficient of the a term and what is the constant
Mathematics
1 answer:
Alex73 [517]3 years ago
5 0
Answer: \\ {( {x}^{2} + 4) }^{2} + 32 = 12 {x}^{2} + 48 \\ \Leftrightarrow {a}^{2} + 32 = 12( {x}^{2} + 4) \\ \Leftrightarrow {a}^{2} + 32 = 12a \\ \Leftrightarrow {a}^{2} - 12a + 32 = 0 \\ \Rightarrow Coefficients:1, \: -12. \: Constant:a
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Answer:

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Step-by-step explanation:

Given: $ \frac{((a^2)^{-2})^5}{a^4.a^3} $

We know that when the bases are same the powers can be added. i.,e.,

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