10m+27 you add the sides to find perimeter so add 2m+2m+2m and so on and it gives u 10m+27
Expand the following:
(x - 6) (3 x^2 + 10 x - 1)
Hint: | Multiply out (x - 6) (3 x^2 + 10 x - 1).
| | | | x | - | 6
| | 3 x^2 | + | 10 x | - | 1
| | | | -x | + | 6
| | 10 x^2 | - | 60 x | + | 0
3 x^3 | - | 18 x^2 | + | 0 x | + | 0
3 x^3 | - | 8 x^2 | - | 61 x | + | 6:
Answer: 3 x^3 - 8 x^2 - 61 x + 6 Thus B:
The measures of the four angles of quadrilateral ABCD are 36°, 72°, 108° and 144°
<u>Explanation:</u>
A polygon has three or more sides.
Example:
Triangle has 3 sides
Square has 4 sides
Pentagon has 5 sides and so on.
27)
In a quadrilateral ABCD, the measure of ZA, ZB, ZC and ZD are the ratio 1 : 2 : 3 : 4
We know,
sum of all the interior angles of a quadrilateral is 360°
So,
x + 2x + 3x + 4x = 360°
10x = 360°
x = 36°
Thus, the measure of four angles would be:
x = 36°
2x = 2 X 36° = 72°
3x = 3 X 36° = 108°
4x = 4 X 36° = 144°
Therefore, the measures of the four angles of quadrilateral ABCD are 36°, 72°, 108° and 144°
Step-by-step explanation:
With reference to the regular hexagon, from the image above we can see that it is formed by six triangles whose sides are two circle's radii and the hexagon's side. The angle of each of these triangles' vertex that is in the circle center is equal to 360∘6=60∘ and so must be the two other angles formed with the triangle's base to each one of the radii: so these triangles are equilateral.
The apothem divides equally each one of the equilateral triangles in two right triangles whose sides are circle's radius, apothem and half of the hexagon's side. Since the apothem forms a right angle with the hexagon's side and since the hexagon's side forms 60∘ with a circle's radius with an endpoint in common with the hexagon's side, we can determine the side in this fashion:
tan60∘=opposed cathetusadjacent cathetus => √3=Apothemside2 => side=(2√3)Apothem
As already mentioned the area of the regular hexagon is formed by the area of 6 equilateral triangles (for each of these triangle's the base is a hexagon's side and the apothem functions as height) or:
Shexagon=6⋅S△=6(base)(height)2=3(2√3)Apothem⋅Apothem=(6√3)(Apothem)2
=> Shexagon=6×62√3=216
Answer:
=17c−11
Step-by-step explanation:
i hope this helps you
