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creativ13 [48]
4 years ago
12

Suppose you do work on an object from rest to a certain speed v. Why does it take four times the amount of work to increase its

speed from rest to a speed of 2v?
Physics
1 answer:
Otrada [13]4 years ago
8 0
Answer: it is due to friction.

Explanation: if you were to push an object that is at rest, there is static friction that you would first need to overcome. An example would be pushing a car as it is in neutral. Pushing it takes more force and work to overcome that friction.
But once it overcomes static, it will then turn to kinetic friction. Once the car starts to move, you notice that it is easier to push. This is due to the fact that kinetic friction would equal normal force times the constant while the static friction is greater than or equal to the normal force times the constant.

Hope this helps!!!
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The weight of a 72.0 kg astronaut on the Moon, where g = 1.63 m/s2 is (5 points) Select one: a. 112 N b. 117 N c. 135 N d. 156 N
Hunter-Best [27]

Answer: The weight of a 72.0 kg astronaut on the Moon is 117.36 N.

Explanation:

Mass of the astronaut on the moon , m= 72 kg

Acceleration due to gravity on moon,g  = 1.63 m/s^2

According to Newton second law of motion: F = ma

This will changes to = Weight = mass × g

Weight=72 kg\times 1.63m/s^2=117.36 N

The weight of a 72.0 kg astronaut on the Moon is 117.36 N.

5 0
4 years ago
Read 2 more answers
What is a wave called that moves up and down
charle [14.2K]
Transverse waves is what its called
7 0
4 years ago
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Which object below would likely show the largest effort of air resistance when falling
blsea [12.9K]
The correct answer is C.) a leaf
7 0
3 years ago
12. A cross-country race car driver sets out on a 1.00 hour, 100.0 km race. At the halfway marker
Akimi4 [234]

Answer:

A.) Time = 0.625 hrs = 37.5 minutes

B.) Speed required = 133.33km/hr

Explanation:

Given the following :

Total race distance = 100km

Total time required = 1 hour = 60 minutes

Average speed after traveling 50km = 80km/hr

80km/hr : This means it will take one hour to cover a distance of 80km

Therefore, time taken to cove first 50km at that average speed equals :

1 hour = 80 km

t hours = 50km

80t = 50

t = 50/80

t = 5/8 hours

t = 0.625hours

t = 0.625 * 60 = 37.5minutes

B)

Average speed required to complete the race in 1 hour = 100km/hr

Time used to complete first 50km = 0.625 hour

Time remaining: (1 - 0.625) hour = 0.375

Speed required = Distance left / time left

Speed required = 50 / 0.375

Speed required = 133.33km/hr

8 0
3 years ago
1
ehidna [41]

Answer:

a = -1.6\ m/s^2

Explanation:

<u>Accelerated Motion</u>

It occurs when an object changes its speed over time. If the changes in speed are uniform, then the acceleration is constant, positive if the speed increases, negative if the speed decreases.

The acceleration is calculated as follows:

\displaystyle a=\frac{v_f-v_o}{t}

The aeroplane starts with a speed of vo=62 m/s and reaches a speed of vf=6 m/s in t=35 s.

The acceleration is:

\displaystyle a=\frac{6-62}{35}=-\frac{56}{35}

\mathbf{a = -1.6\ m/s^2}

3 0
3 years ago
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