<span>This problem is solved by the equation of motion:
x = x0 + v0*t + 1/2*a*t^2,
Here x0 = 0, v0 = 40ft/sec and a = -5 ft/s^2, we need to solve for t:
v = v0 + a*t, solve how long does it take to stop: 0 = v0 + a*t --> a*t = -v0 --> t = -v0/a
-- > 40/5 = 8 seconds to stop.
In this time, the car travels x = 0 + 40*8 + 0.5*-5*8^2 ft ~ 160 ft.
Answer: The car travels 160 ft.</span>
Answer:
The maximum height of the ball is 20 m. The ball needs 2 s to reach that height.
Explanation:
The equation that describes the height and velocity of the ball are the following:
y = y0 + v0 · t + 1/2 · g · t²
v = v0 + g · t
Where:
y = height of the ball at time t
y0 = initial height
v0 = initial velocity
t = time
g = acceleration
v = velocity at time t
When the ball is at its maximum height, its velocity is 0, then, using the equation of the velocity, we can calculate the time at which the ball is at its max-height.
v = v0 + g · t
0 = 20 m/s - 9.8 m/s² · t
-20 m/s / -9.8 m/s² = t
t = 2.0 s
Then, the ball reaches its maximum height in 2 s.
Now, we can calculate the max-height obtaining the position at time t = 2.0 s:
y = y0 + v0 · t + 1/2 · g · t²
y = 0 m + 20 m/s · 2 s - 1/2 · 9,8 m/s² · (2 s)²
y = 20 m
Incomplete question. However, I provided a brief about Kinetic energy generation.
<u>Explanation:</u>
Interestingly, Kinetic energy in simple terms refers to the energy possessed by a body in motion.
It is often calculated using the formula E = 
A good example of creating even more kinetic energy is a hand crank toy car that moves after you wind it a little, when the car moves it is generating another measure of K.E.
The amount of cytoplasm I think.
