The given reaction is incomplete. The complete reaction is as follows.
Ammonium phosphate is an important ingredient in many solid fertilizers. It can be made by reacting aqueous phosphoric acid with liquid ammonia. Calculate the moles of phosphoric acid needed to produce 1.30 mol of ammonium phosphate. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.
Explanation:
Chemical equation for the given reaction is as follows.
Therefore, moles of required will be calculated as follows.
= 1.30 mol
Therefore, we can conclude that the moles of phosphoric acid needed to produce 1.30 mol of ammonium phosphate are also 1.30 mol.
This solution is "supersaturated".
A supersaturated solution is a solution that contains a higher than than the concentration of solute, slight unsettling influence or seeding causes crystallization of abundance solute.
Supersaturation is a condition of a solution that contains a greater amount of the dissolved material than could be dissolved by the solvent under ordinary conditions.
Answer:
0.51M
Explanation:
Given parameters:
Initial volume of NaBr = 340mL
Initial molarity = 1.5M
Final volume = 1000mL
Unknown:
Final molarity = ?
Solution;
This is a dilution problem whereas the concentration of a compound changes from one to another.
In this kind of problem, we must establish that the number of moles still remains the same.
number of moles initially before diluting = number of moles after dilution
Number of moles = Molarity x volume
Let us find the number of moles;
Number of moles = initial volume x initial molarity
Convert mL to dm³;
1000mL = 1dm³
340mL gives = 0.34dm³
Number of moles = initial volume x initial molarity = 0.34 x 1.5 = 0.51moles
Now to find the new molarity/concentration;
Final molarity = = = 0.51M
We can see a massive drop in molarity this is due to dilution of the initial concentration.