A^2=b^2+c^2-2bc Cos(A)
(270)^2=(255)^2+(442.85)^2-2(255)(442.85)Cos(A)
A=Cos^(-1)(270^2-255^2_(442.85)^2)/(-2*255*442.85)=33.5435
solve for angle A approximately is 33.54 degrees.
sinA/a=SinB/b
Sin33.54/270=SinB/255
B=Sin^(-1)(sin33.54/270*255)approximately is 31.45.
180-31.45-33.54=115.01 is Angle C.
16x + 21y = 555
Step-by-step explanation:
Let x be the no. of 18-hole course
And y be the no. of golf balls
16x + 21y = 555
8505. You would do 63 times 135 to get 8505
The little lines on each side of the rhombus mean that all the sides are the same length.
We can set line LM and MN equal to solve for X, then we can solve the length of a side.
3x-3 = x+7
Add 3 to each side:
3x = x +10
Subtract x from each side:
2x = 10
Divide both sides by 2:
x = 10/2
x = 5
Now we have the value for x, replace x in one of the side formulas:
x +7 = 5+7 = 12
Each side = 12 units.
The perimeter would be 12 + 12 + 12 + 12 = 48 units.
Answer: The tenth term in the sequence is 512.
Step-by-step explanation:
Since we have given that
We need to find the tenth term:
It means n = 10
So, it becomes
Hence, the tenth term in the sequence is 512.
