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soldier1979 [14.2K]
3 years ago
10

Six more than the product of a number and 3 equals 7. Translate the sentence into an equation.

Mathematics
1 answer:
USPshnik [31]3 years ago
5 0
7 = 3a + 6 should be your answer
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The admission to a local fair is $10 for each adult and $6 for each child. Each ride costs $1.50 for an adult and $1 for a child
S_A_V [24]
So first start out by writing an expression for the cost of the child and the adult separately.

Child:
6 + 1r   ($6 + $1 per ride)

Adult:
10 + 1.5r   ($10 + $1.50 per ride)

to find how much more the adult will spend, just do Adult Expression - Child Expression which will be:

10 + 1.5r - (6 + 1r)  just simplify this

For Part B, use your equation from part A where r = 7
6 0
2 years ago
The Walking Club is one of the after-school activities at Jefferson Middle School.
saveliy_v [14]

You first need to know how much miles it takes on the trail. Then you look 20 x 3 is one hour. And if the 3 group said it takes 2 hours waking for them its like this, the first group takes one hour to go thru the trail, but the second group takes and hour and half the 3 group takes 2 hours.

I wish this helps. :)

4 0
3 years ago
Witch expersson is equivalent to 4x-5?
barxatty [35]

Answer:

Uh where are the other expressions?

Step-by-step explanation:

7 0
2 years ago
Solve the following system by graphing.<br> Y =<br> 2 + 5<br> y = -x-1
Klio2033 [76]

Answer:

Step-by-step explanation:

2x + 5 = -x  - 1

3x + 5 = -1

3x = -6

x = -2

y = 2 - 1

y = 1

(-2, 1)

4 0
3 years ago
Which of the following operations is true regarding relative frequency distributions? Multiple choice question. No two classes c
pshichka [43]

Answer:

The relative frequency is found by dividing the class frequencies by the total number of observations

Step-by-step explanation:

Relative frequency measures how often a value appears relative to the sum of the total values.

An example of how relative frequency is calculated

Here are the scores and frequency of students in a maths test

Scores (classes)              Frequency                Relative frequency

0 - 20                                10                               10 / 50 = 0.2

21 - 40                               15                               15 / 50 = 0.3

41 - 60                               10                               10 / 50 = 0.2

61 - 80                                5                                 5 / 50  = 0.1

81 - 100                             <u> 10</u>                                10 / 50 = <u>0.2</u>

                                          50                                               1

From the above example, it can be seen that :

  1. two or more classes  can have the same relative frequency
  2. The relative frequency is found by dividing the class frequencies by the total number of observations.
  3. The sum of the relative frequencies must be equal to one
  4. The sum of the frequencies and not the relative frequencies is equal to the number of observations.

4 0
2 years ago
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