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3 years ago

the sum of two numbers is 18. twice the first number increased by three times the second number equals 40. find the numbers

Mathematics

1 answer:

ryzh [129]3 years ago

7 0

Answer:

4 and 14

Step-by-step explanation:

:the sum of two numbers is 18" can be written as

x + y = 18 let x represent the first number, and y the second

"twice the first number increased by three times the second number equals 40" can be written as

2x + 3y = 40

Now solve this system. Using elimination will probably be the easier method...

1. x + y = 18

2. 2x + 3y = 40

Multiply equation 1 by -2 so the x variable will be the opposite of the x variable on equation 2.

1. -2x - 2y = -36

2. 2x + 3y = 40

Now add the equations together, cancelling out 'x'

y = 4 ( 2x + (-2x) = 0, so 'x' is gone, 3y + (-2y) = y, 40 + (-36) = 4)

Since y = 4, plug that into either equation 1 or 2 and solve for x

1. x + 4 = 18 (y becomes 4)

x = 14 (subtract 4 on both sides to isolate 'x')

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Anettt [7]

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[When an exponent is negative, you move it to the other side of the fraction to make the exponent positive.]

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You need to determine the solution of f(x) = g(x)

Since you know f(x) = 9x + 7 and $g(x)=5^x$ , you can plug in (9x + 7) for f(x), and ( $5^x$ ) into g(x)

f(x) = g(x)

$9x+7=5^x$ You can plug in each value of x into the equation

Your answer is x = 2 because when you plug in 2 for x in the equation, you get 25 = 25

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