Answer:
acceleration=force/mass
Due to variation in the mass[ as same force as per magnitude acts on both of them] the acceleration developed in the bug will be more and the acceleration developed in the car is negligible.
impulse=change in momentum
The impulse of bug is more and that of car is small.
momentum changes=change in momentum
force=change in momentum/time of contact
the force exerted by car on the bug will be more than the converse
Total. momentum is conserved , so magnitude of change in momemtum or impulse is same. By Newtons third law, since the bug have smaller mass, its change in magnitude of velocity is larger.
Step-by-step explanation:
Answer:
D.
Step-by-step explanation:
Remember that the limit definition of a derivative at a point is:
![\displaystyle{\frac{d}{dx}[f(a)]= \lim_{x \to a}\frac{f(x)-f(a)}{x-a}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28a%29%5D%3D%20%5Clim_%7Bx%20%5Cto%20a%7D%5Cfrac%7Bf%28x%29-f%28a%29%7D%7Bx-a%7D%7D)
Hence, if we let f(x) be ln(x+1) and a be 1, this will yield:
![\displaystyle{\frac{d}{dx}[f(1)]= \lim_{x \to 1}\frac{\ln(x+1)-\ln(2)}{x-1}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%281%29%5D%3D%20%5Clim_%7Bx%20%5Cto%201%7D%5Cfrac%7B%5Cln%28x%2B1%29-%5Cln%282%29%7D%7Bx-1%7D%7D)
Hence, the limit is equivalent to the derivative of f(x) at x=1, or f’(1).
The answer will thus be D.
So a²+b²=c²
8²+15²=c²
64+225=c²
289=c²
±17=c
So c=17 or c=-17
Answer:
(x + 9)(x + 2 )
Step-by-step explanation:
Sum =11
Product = 18
Factors = 9 , 2
When you multiply (9*2 = 18) and when you add (9 +2 = 11).
x² + 11x + 18 = x² + 9x + 2x + (9*2)
=x(x + 9) + 2(x + 9)
= (x + 9)(x + 2 )