Answer: y=1/2x+5/2
Step-by-step explanation:
y-3=1/2 (x-1)
y-3(-3)=1/2x-1/2(+3)
y=1/2x-1/2+6/2
y=1/2x+5/2
hope this helped!!
Answer:
Input:
x/x + 1 - 1/x - 1 + 2×x/x^2 - 1
Result:
1/x
Functions: the chart with number values, the dot graph, and the middle graph on the right
Not functions: the top graph on the left with the vertical line, the graph with the circle, and the bottom right graph
Any graph that doesn’t pass the vertical line test is not a function. You can do this by starting at the top of the graph and drawing a line straight down through what you are testing. If you pass through the line or circle more than once it is not a function.
If you look at the number values if the x value repeats more than once it is not a function.
no it isn't. 2cos(x) is 2 multiplied by cos(x), cos (2x) is cos(2 multiplied by x) meaning 2x is the angle you're taking the cosine of. if you want to know what cos(2x) look up the double angle rule.
Hi there,
This is the original inequality equation:

So, we first need to find the critical points of equality, and we can do that by switching the less than sign to an equal sign.

Now, we multiply both sides by x + 1:

Then, we multiply both sides by x - 1:

Next, we subtract x² from both sides:

After that, we solve for x. We do this by adding -x to both sides and dividing by 2. Doing so gives us x = 0, which is our first critical point. We need to find a few more critical points by testing x = -1 and x = 1. Here is how we do that:
<span>x = <span>−1 </span></span>(Makes left denominator equal to 0)<span>x = 1 </span>(Makes right denominator equal to 0)Check intervals in between critical points. (Test values in the intervals to see if they work.)<span>x <<span>−1 </span></span>(Doesn't work in original inequality)<span><span><span>−1 </span>< x </span><0 </span>(Works in original inequality)<span><span>0 < x </span>< 1 </span>(Doesn't work in original inequality)<span>x > 1 </span><span>(Works in original inequality)
Therefore, the answer to your query is
-1 < x < 0 or x > 1. Hope this helps and have a phenomenal day!</span>