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Tcecarenko [31]
2 years ago
12

How does dividing mixed number compare with dividing fractions?

Mathematics
1 answer:
Orlov [11]2 years ago
5 0
Dividing mixed numbers is when you take a mixed number divided by a mixed number and make then fractions. Here's an example:
(Example)~5 1/5 divided by 3 1/3
5x5=25+1=26. 26/5
3x3=9+1=10/3
26/5 divided by 10/3= 26/5 multiplied by 3/10= 78/50
Dividing Fractions is when you turn 2 fractions and make them into a multiplication problem. Here's an example:
(Example)~ 2/3 divided by 4/8
2/3 multiplied by 8/4
2/3 x 8/4= 16/12~ Which turns into 1 4/12
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Answer:

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Step-by-step explanation:

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3 years ago
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I need help with coming up with equation
Natali5045456 [20]

Let's call a child's ticket c and an adult's ticket a. From this, we can say:

c + a = 116,

since 116 tickets are sold in total.


Now, we are going to need to find another equation (the problem asks us to solve a systems of equations). This time, we are not going to base the equation on ticket quantity, but rather ticket price. We know that an adult's ticket is $17,000, and a child's ticket is thus

\$17000 \cdot (1 - \dfrac{1}{4}) = \$12750.


Given these values, we can say:

17000a + 12750c = 1653250,

since each adult ticket a costs 17,000 and each child's ticket c costs 12,750, and these costs sum to 1,653,250.


Now, we have two equations:

17000a + 12750c = 1653250

c + a = 116


Let's solve:

17000a + 12750c = 1653250

a = 116 - c

  • Find a on its own, which will allow us to substitute it into the first equation

17000(116 - c) + 12750a = 1653250

  • Substitute in 116 - c for a

1972000 - 17000c + 12750c = 1653250

  • Apply the Distributive Property

1972000 - 4250c = 1653250

  • Combine like terms

4250c = 318750

  • Subtract 1972000 from both sides of the equation and multiply both sides by -1

c = 75


We have now found that 75 child's tickets were sold. Thus,

75 + a = 116 \Rightarrow a = 116 - 75 = 41,

41 adult tickets were sold as well.


In sum, 41 adult tickets were sold along with 75 child tickets.

6 0
3 years ago
Three sets have 5, 10, 15 elements, respectively. How many elements can their union and intersection have?​
Degger [83]

Answer:

Union = 15

Step-by-step explanation:

Given

n(A) = 5; n(B) = 10; n(C) = 15

Solving (a): Possible union elements

This is the represented by element with the largest number of the sets

i.e.

Union = 15

Solving (b): Possible intersection elements

This is the represented by element with the least number of the sets

i.e.

Intersection = 5

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Nadya [2.5K]
Because 4x2 = 8, so 4x7=28, then you times 28 by 2 which equals 56 and 8x7=56
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The Best Buy would be the 24 oz. box.
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