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Verdich [7]
3 years ago
5

In what form is the following linear equation written? y-3=2/3(x-1)

Mathematics
2 answers:
podryga [215]3 years ago
4 0

Answer:

point-slope

Step-by-step explanation:

lions [1.4K]3 years ago
3 0
First we solve what we can solve.
<span>y</span>-3= 2/3<span>(</span>x-1)
We first multiply
<span>y</span>-3= 2/3 (x) - 2/3
Then we move the -3 and it becomes +3 on the other side
y= 2/3 (x) - 2/3 + 3
And we solve what we can to get our answer.
y= 2/3 (x) + 2 1/3
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Yuki888 [10]

Answer:

Las Vegas

Step-by-step explanation:

4 0
3 years ago
I put a picture
Ksivusya [100]

Answer:

Yes, an arrow can be drawn from 10.3 so the relation is a function.

Step-by-step explanation:

Assuming the diagram on the left is the domain(the inputs) and the diagram on the right is the range(the outputs), yes, an arrow can be drawn from 10.3 and the relation will be a function.

The only time something isn't a function is if two different outputs had the same input. However, it's okay for two different inputs to have the same output.

In this problem, 10.3 is an input. If you drew an arrow from 10.3 to one of the values on the right, 10.3 would end up sharing an output with another input. This is allowed, and the relation would be classified as a function.

However, if you drew multiple arrows from 10.3 to different values on the right, then the relation would no longer be a function because 10.3, a single input, would have multiple outputs.

3 0
3 years ago
Simplify the expression by combining like terms 2x+8-x+10
svp [43]

Answer:

x+18

Step-by-step explanation:

Let's simplify step-by-step.

2x+8−x+10

=2x+8+−x+10

Combine Like Terms:

=2x+8+−x+10

=(2x+−x)+(8+10)

=x + 18

8 0
3 years ago
The equation y = 0.25x describes a proportional relationship between x and y. What is the constant of proportionality?
hoa [83]

Answer:

k = 0.25

Step-by-step explanation:

The standard equation of a proportional relationship is

y = kx ← k is the constant of proportion

y = 0.25x ← is in this form

with k = 0.25

8 0
3 years ago
Consider the function attached below
Masja [62]

Answer:

2

Step-by-step explanation:

Hello,

x=(fof^{-1})(x)=f(f^{-1}(x))=\sqrt{2f^{-1}(x)}+5\\\sqrt{2f^{-1}(x)} =x-5\\2f^{-1}(x)=(x-5)^2\\f^{-1}(x)=\dfrac{(x-5)^2}{2}

now let's replace x by 7 it comes

f^{-1}(7)=\dfrac{(7-5)^2}{2}=\dfrac{2^2}{2}=2

hope this helps

4 0
3 years ago
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