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krek1111 [17]
4 years ago
9

Please help with 15, 17 and 19

Mathematics
1 answer:
Irina-Kira [14]4 years ago
6 0

Given:

15. \log_{\frac{1}{2}}\left(\dfrac{1}{2}\right)

17. \log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)

19. 2^{\log_2100}

To find:

The values of the given logarithms by using the properties of logarithms.

Solution:

15. We have,

\log_{\frac{1}{2}}\left(\dfrac{1}{2}\right)

Using property of logarithms, we get

\log_{\frac{1}{2}}\left(\dfrac{1}{2}\right)=1         [\because \log_aa=1]

Therefore, the value of \log_{\frac{1}{2}}\left(\dfrac{1}{2}\right) is 1.

17. We have,

\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)

Using properties of logarithms, we get

\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)=-\log_{\frac{3}{4}}\left(\dfrac{3}{4}\right)                    [\because \log_a\dfrac{m}{n}=-\log_a\dfrac{n}{m}]

\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)=-1                 [\because \log_aa=1]

Therefore, the value of \log_{\frac{3}{4}}\left(\dfrac{4}{3}\right) is -1.

19. We have,

2^{\log_2100}

Using property of logarithms, we get

2^{\log_2100}=100          [\because a^{\log_ax}=x]

Therefore, the value of 2^{\log_2100} is 100.

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