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Firdavs [7]
3 years ago
12

Describe the transformation from the graph of f(x)= x^3to the graph of g(x)=(x+1)3+12

Mathematics
1 answer:
wel3 years ago
4 0

Step-by-step explanation:

sayang awak selamanya

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XD me banearon de nuevo pero regrese igualmente no me pueden moderadores.
aleksandrvk [35]

Answer:

yeah what you said

7 0
3 years ago
What value of b will cause the system to have
Tresset [83]

9514 1404 393

Answer:

  6

Step-by-step explanation:

The value of b that makes the two lines identical is the opposite of the y-intercept of the line.

  y = 6x -6 . . . . has y-intercept = -6

The value of b is the number in the term -6, so is 6.

5 0
3 years ago
Please help I don't understand this
Dmitrij [34]
4>-3
-2>-5
1=1


They want to make sure you understand inequalities and know how to use the inequality signs.
5 0
4 years ago
Read 2 more answers
Eli has saved $8 more than 1/3 of Angela’s savings.If they each save $10 more Eli will have saved &4 more than Angela’s savi
klasskru [66]

Answer:

$34

Step-by-step explanation:

7 0
4 years ago
Six sophomores and 14 freshmen are competing for two alternate positions on the debate team. Which expression represents the pro
Elanso [62]

Answer:

<em>Choose the first alternative</em>

\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}

Step-by-step explanation:

<u>Probabilities</u>

The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions (N_s) and the total number of possible choices (N_t), i.e.

\displaystyle P=\frac{N_s}{N_t}

There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total

We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.

To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5

_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C} \text{ ways to do it}

The total number of possible choices is

_{2}^{20}\textrm{C} \text{ ways to do it}

The probability is then

\boxed{\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}}

Choose the first alternative

7 0
3 years ago
Read 2 more answers
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