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3 years ago

14

A sample of gas occupies a volume of 450.0 ML at 740 mm Hg and 16c determine the volume of this sample at 760mm Hg and 37C show

work please

2 answers:

romanna [79]3 years ago

6 0

Answer:

474.92 mL

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n is constant, and have two different values of (P, V and T):

P₁V₁T₂ = P₂V₂T₁

P₁ = 740 mmHg, V₁ = 450 mL, T₁ = 16°C + 273 = 286 K.

P₂ = 760 mmHg, V₂ = ??? mL, T₂ = 37°C + 273 K = 310 K.

∴ V₂ = P₁V₁T₂/P₂T₁ = (740 mmHg)(450 mL)(310 K)/(760 mmHg)(286 K) = 474.92 mL.

algol133 years ago

5 0

Answer:

474.92 mL.

Explanation:

We can use the general law of ideal gas: <em>PV = nRT</em>.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n is constant, and have two different values of (P, V and T):

<em>P₁V₁T₂ = P₂V₂T₁</em>

<em></em>

P₁ = 740 mmHg, V₁ = 450 mL, T₁ = 16°C + 273 = 286 K.

P₂ = 760 mmHg, V₂ = ??? mL, T₂ = 37°C + 273 K = 310 K.

<em>∴ V₂ = P₁V₁T₂/P₂T₁ </em>= (740 mmHg)(450 mL)(310 K)/(760 mmHg)(286 K) = <em>474.92 mL.</em>

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