Answer:-
7.03 g
Explanation:-
Let the mass of water needed be M.
So total mass = M + 0.37
Now 5% of this solution has 0.37g of rubidium chlorude.
∴ (M +0.37) x (5/100) = 0.37
M +0.37 = 0.37 x 100/5
M + 0.37 = 7.4
M = 7.4-0.37
=7.03
Thus water to be added is 7.03 gram
Answer:
See explaination
Explanation:
Please kindly check attachment for the step by step solution of the given problem.
What do you mean by unlock all of them? Please explain
Answer:
16.7 mL
Explanation:
Convert 250 mL to L.
250 mL = 0.250 L
Calculate the amount of moles of NaOH in 250 mL of 0.300 M NaOH.
0.250 L × 0.300 M = 0.075 mol
Using this amount of moles, you need to find out what volume of 4.50 M will give you that many moles. You can do this by dividing the amount of moles by the molarity.
(0.075 mol)/(4.50 M) = 0.0167 L
Convert from L to mL.
0.0167 L = 16.7 mL
