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Nana76 [90]
3 years ago
13

Electric current is the flow of particles with ________. a. Negative charge b. Positive charge c. Both positive and negative cha

rges flowing opposite to each other. d. Either positive or negative charge depending on the material
Chemistry
2 answers:
bonufazy [111]3 years ago
8 0

Answer:A

Explanation:Electricity is negative charge

Lelechka [254]3 years ago
4 0
I believe Positive & Negative
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A first order reaction has 1/16 of the original amount left after 500 seconds. What is the half-life of the reactant in this rea
jonny [76]

A first order reaction, with a half-life of 125 s, has 1/16 of the original amount left after 500 seconds.

<h3>What is a first order reaction?</h3>

It is a chemical reaction in which the rate of reaction is directly proportional to the concentration of the reacting substance.

First, we will calculate the rate constant using the following expression.

ln ([A]/[A]₀) = - k × t

ln (1/16[A]₀/[A]₀) = - k × 500 s

k = 5.55 × 10⁻³ s⁻¹

where,

  • [A] is the final concentration of the reactant.
  • [A]₀ is the initial concentration of the reactant.
  • k is the rate constant.
  • t is the elapsed time.

Next, we can calculate the half-life (th) using the following expression.

th = ln 2 / k = ln 2 / (5.55 × 10⁻³ s⁻¹) = 125 s

A first order reaction, with a half-life of 125 s, has 1/16 of the original amount left after 500 seconds.

Learn more about first order reactions here: brainly.com/question/518682

5 0
2 years ago
Between Lab Period 1 and Lab Period 2, design a separation scheme for all 4 cations. Use the results of your preliminary tests a
fiasKO [112]

Answer:

                    SEPARATION SCHEME FOR  CATIONS

GIVEN  CATIONS : Ag^{+} \ ,  Fe^{3+} , Cu^{2+}, Ni^{2+}

     

    Step 1:   Add 6mol/dm^3 of HCl to the mixture solution

    Result : This would cause a precipitate of AgCl to be formed

    Reaction :  Ag^{+} _{(aq)} + Cl^{-} _{(aq)}  ---------> AgCl(ppt)

    Step 2 : Next is to remove the precipitate and add H_2S to the remaining          

                 solution in the presence of 0.2 \ mol/dm^3 of HCl

     Result : This would cause a precipitate of CuS to be formed

     Reaction :  Cu^{2+}_{(aq)} + S^{2-}_{(aq)} ------> Cu_2S(ppt)

 

     Step 3: Next remove the precipitate then add 6 \ mol/dm^3 of aqueous      

                 NH_3 (NH_3 \cdot H_2 O) , process the solution in a centrifuge,when the  

                 process  is done then sort out the  precipitate from the  solution

                 Now this precipitate is   Fe(OH)_3 and the remaining solution

                contains  (Ni (NH_3)_6)

                 Next take out the precipitate to a different beaker and add HCl

                to it   this will dissolve it, then add a drop of NH_4SCN this will

                form  a precipitate  Fe(SCN)_{6}^{3-} which will have the color of

                 blood  indicating the presence of Fe^{3+}

             

   Reaction :   F^{3+}_{(aq)} + 30H^-_{(aq)} --------->Fe(OH)_3_{(aq)}

                        Fe (OH)_{(s)} _3  + 3H^{+}_{aq} -------> Fe^{3+}_{aq} + 3H_2O_{(l)}

                         Fe^{3+} + 6SCN^{-} -----> Fe(SCN)_6 ^{3-}

                      Now the remaining mixture contains Ni^{2+}

     

       

Explanation:

6 0
4 years ago
2503(g) → 2502(g) O2(g)
Verizon [17]

Answer:

7.146

Explanation:

use the equilibrium equation

6 0
3 years ago
When magnesium ribbon is ignited, it gives off a white fume of magnesium oxide. What is this type of reaction? synthesis reactio
lapo4ka [179]
It is an oxidation reaction 

6 0
4 years ago
Pure iron has a mass of 5.00 grams what’s the calculation of its volume
mart [117]

Answer:

0.635 cm³

Explanation:

You divide the mass by the density of iron (7.87 g/cm³)

<em>D = m</em>/<em>V</em>                Multiply both sides by V.

<em>DV = m</em>                 Divide both sides by D.

<em>V</em> = <em>m</em>/<em>D</em>                Insert the values.

<em>V </em>= 5.00/7.87      Do the division.

<em>V</em> = 0.635 cm³

5 0
3 years ago
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