Answer:
B- 8 ounces of blue paint mixed with 6 ounces of red paint
D - 20 ounces of blue paint mixed with 15 ounces of red paint
Answer:
133/143
Step-by-step explanation:
Let S be the sample space
Let E be the event of selecting three committee partners with at least one junior partner.
Partners in the law firm include:
Senior partners = 6
Junior partners = 7
Total partners = 13
n(S) = number of ways of selecting 3 partners from 13 = 13C3
n(S) = 13C3 = 13!/(10!3!) = (13x12x11)/(3x2x1) = 286
To get n(E) i.e least 1 junior partner in the selected committee, we may have:
(2 senior and 1 junior) or ( 1 senior and 2 junior) or (3 junior).
Therefore, the required number of way is given below:
= (6C2 x 7C1) + (6C1 x 7C2) + 7C3
= [(6x5)/2 x 7] + [6 x (7x6)/2] + [(7x6x5)/(3x2)]
= 105 + 126 + 35
n(E) = 266
Therefore, the probability P(E) that at least one of the junior partners is on the committee is given below:
P(E) = n(E) /n(S)
P(E) = 266/286
P(E) = 133/143
5 People can be chosen in 1287 ways if the order in which they are chosen is not important.
Step-by-step explanation:
Given:
Total number of students= 13
Number of Students to be selected= 5
To Find :
The number of ways in which the 5 people can be selected=?
Solution:
Let us use the permutation and combination to solve this problem
So here , n =13 and r=5 ,
So after putting the value of n and r , the equation will be
Correct Answer: 10 students have never visited another state
40/100 × 25 =
40 is out of 100 because percentages always is represented by 100 (cent)
cross out the zero's equally top and bottom
so it would become: 4/100 × 25 = 4 ×25 = 100
then add the denominator
100/10 is our final resolution
cross out the zeros evenly and answer will give you 10.
Answer:
yes
Step-by-step explanation:
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