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3 years ago

A concrete stepping stone measures 20 inches square. What is the area of 30 such tiles?

2 answers:

7 0

A single stepping stone as you have said is 20 inches sqaure. This means that it has an area of 20.

All you would need to do then is multiply 20 by 30 to get the area of thirty tiles. The result of this would be 600.

If you mean one side of the stepping stone is 20 inches then you would multiply 20 by 20 to get the area of one, since that would be multiplying length times width (the area formula). The area of one would result in 400 and you would then multiply this by the thirty tiles (400 times 30) to get 12000.

Tcecarenko [31]3 years ago

3 0

600 inches square (600 in²) is the total area of 30 such tiles

A concrete stepping stone measures 20 inches square
The area of 30 such tiles is = ?

<h2>Further Explanation</h2>

Since a single stepping stones = 20 inches square

To determine the area of the 30 such tiles, then you should multiply the area of 30 such tiles by what a single stepping stones measures (20 inches square)

Therefore we have:

= 30 x 20

= 600

So, 600 inches square is the total area of 30 such tiles. (600 in²)

Notably, a concrete stepping stones that measures 20 inches square also implies it has an area of 20 inches square.

We solve this question with the aid of multiplication, which is one of the functions of BODMAS.

LEARN MORE:

A concrete stepping stone measures 20 square inches what is the area of 30 such stones brainly.com/question/360871
A concrete stepping stone measures 20 inches square. What is the area of 30 such tiles brainly.com/question/738709

KEYWORDS:

bodmas
30 such tiles
20 inches square
multiplying
stepping stones measure

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<h3>How to find the side of a right triangle?</h3>

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The sides CD and BD can be found using similar triangle principle.

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Answer:

See Explanation

Step-by-step explanation:

Given

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$Length: 10\ in$

$Width: 8\ in$

Required

Determine the possible dimensions of Rectangle B

<em>The question has missing options; however, the question can still be solved.</em>

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