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3 years ago

What is the area of an equilateral triangle whose altitude is 6？

Mathematics

2 answers:

zhuklara [117]3 years ago

8 0

Answer:

the answer is attached to the picture

hope this helps

brainliest appreciated

good luck! have a nice day!!

sweet [91]3 years ago

6 0

So the right answer is 15.57.

Look at the attached picture

Hope it will help you..

Good luck on your assignment

~pragya

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2/5(d−10)−2/3(d+6) is

MissTica

Remove parentheses
2/5 • d-10 - 2/3 • d+6

calculate
2/5d-4 - 2/3d-4

the answer
-4/15d-8

3 0

3 years ago

Calculate the area of the quarter circle estimate using 3.14 for pi

mars1129 [50]

The area of the quarter circle with radius 3ft is $7.065 ft^2$

Area of a quarter circle is given by the formula:

$Area = \frac{\pi r^2}{4}$

Where r represents the radius of the circle

In the quarter circle shown, the radius, r = 3 feet

π = 3.14

Substitute π = 3.14 and r = 3 into the formula $Area = \frac{\pi r^2}{4}$

$Area = \frac{3.14 \times 3^2}{4}\\\\Area = \frac{3.14 \times 9}{4}\\\\Area = \frac{28.26}{4}\\\\Area = 7.065 ft^2$

The area of the quarter circle with radius 3ft is $7.065 ft^2$

Learn more here: brainly.com/question/25843249

6 0

3 years ago

CALCULUS: For an object whose velocity in ft/sec is given by v(t) = sin(t), what is its distance, in feet, travelled on the inte

rodikova [14]

The linked answer is wrong because that integral gives you the net displacement of the object, not the total distance.

To get the distance, you have to integrate the speed (as opposed to velocity), which involves integrating the absolute value of the velocity function.

$\mathrm{distance} = \displaystyle\int_1^5 |\sin(t)| \,\mathrm dt$

By definition of absolute value,

$|\sin(t)|=\begin{cases}\sin(t)&\text{for }\sin(t)\ge0\\-\sin(t)&\text{for }\sin(t)$

Over this particular integration interval,

• sin(t ) ≥ 0 for 1 ≤ t < π, and

• sin(t ) < 0 for π < t ≤ 5

so you end up splitting the integral at t = π as

$\mathrm{distance} = \displaystyle\int_1^\pi \sin(t)\,\mathrm dt + \int_\pi^5 (-\sin(t))\,\mathrm dt$

Now compute the distance:

$\mathrm{distance} = -\cos(t)\bigg|_1^\pi + \cos(t)\bigg|_\pi^5$

$\mathrm{distance} = -(\cos(\pi) - \cos(1)) + (\cos(5) - \cos(\pi))$

$\mathrm{distance} = -2\cos(\pi) + \cos(1) + \cos(5) \approx 2.82$

making B the correct answer.

7 0

3 years ago

David bought 3 dvds and 4 books for $40 at a yard sale. Anna bought 1 dvd and 6 books for $18. How much did each dvd and book co

Ber [7]

Answer:

A book is worth $1 and a DVD is worth $12.

Step-by-step explanation:

The equations (2 unknowns and two equations, d is for a DVD and b is for a book):

For David: 3d+4b=40

For Anna: d+6b=18

Now multiply the second equation with -3 and add to the first equation:

3d+4b=40

−3d−18b=−54

Combined equation: −14b=−14 and b=1 (means that each book is worth $1).

Now for DVD price, use the second equation:

d=18−6 or d=12 (means that each DVD is worth $12).

A book is worth $1 and a DVD is worth $12.

8 0

3 years ago

The domain of both f(x) = x - 6 and g(x) = x + 6 is all real numbers. What is the domain of h(x) = f(x)/g(x)?

arlik [135]

This is a quotient (division) of two functions we must be concerned with the fact that division by zero is undefined.

Since g(x) is in the divisor position, it cannot equal 0.
$x+6 \neq 0$
$x \neq -6$ Subtract 6 from both sides to solve.
So the domain is all real numbers except -6
Set notation {x | x ∈ R, x ≠ -6}
Interval notation (-∞,-6)∪(-6,∞)

6 0

3 years ago