She uses 1yd for 60 charms, so for 5/8yd she would use 5/8×60=37.5.
Because she can’t use a fraction of a charm, she would use 37 charms which is 37/96 of the charms she has.
Answer:
There would be 10 quarters and 23 dimes.
Step-by-step explanation:
There are generally two methods to solving this type of problem. (1) is guess and check, where you try different amounts of dimes and quarters in combinations of 33 coins until you reach an amount of $4.80. However, we can also solve the problem algebraically using two equations and two variables. In this case, 'd' = amount of dimes and 'q' = amount of quarters. We know that there are 33 total coins, or d + q = 33. We also know that the amount of the coins is $4.80, or .10d + .25q = 4.80. Solving the first equation for 'q', we get q = 33 - d. We can then substitute this expression for 'd' in the second equation to solve for d: .10d + .25(33 - d) = 4.80 or .10d + 8.25 - .25d = 4.80. Combining like terms and using inverse operations, first subtraction then division, we get d = 23. If there are 23 dimes, then there must be 10 quarters, for a total of 33 coins or $2.30 in dimes and $2.50 in quarters.
Answer:
3π
Step-by-step explanation:
The arc length is just a fraction of the circumference of the circle which we know is represented by the equation L=2πr.
The radius is given ad 6. So the circumference is:
2*π*6=12π
Now, since the angle of the arc is 90°, this is 1/4 of the circle.
This means that the arc length of this section will be 1/4th of the total circumference which is:
12π/4=3π