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3 years ago

Find the parallelogram.

Mathematics

2 answers:

jek_recluse [69]3 years ago

8 0

Answer:

area - 120 cm

Step-by-step explanation:

madam [21]3 years ago

5 0

Answer:

A = 120 cm^2

P = 54 cm

Step-by-step explanation:

Area of parallelogram: = base * height

A = 15 cm * 8 cm = 120 cm^2

Perimeter of parallelogram = sum of lengths of sides

P = 15 cm + 15 cm + 12 cm + 12 cm = 54 cm

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Answer:

Step-by-step explanation:

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3 years ago

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Why in division there is sometimes remaindres?

Ksenya-84 [330]

In division problems, if the division results in a decimal or fraction, (not a whole number), than it has a remainder. If the division results in a whole number, then there is no remainder, or a remainder of zero.

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2 years ago

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Need help with this angle don't know what to do with the x

vichka [17]

Hello!

Due to the definition of the Alternate Interior Angles Theorem, (x+23)+(x+54)=180 degrees:

x + 23 + x + 54 = 180
2x + 77 = 180
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x = approximately 52 degrees or exactly 51.5 degrees

I hope this helps :))

4 0

3 years ago

Abraham has visited 10 countries already. He has a goal of visiting at least 50 countries. He plans to achieve this goal by visi

olasank [31]

Given :

Abraham has visited 10 countries already. He has a goal of visiting at least 50 countries.

He plans to achieve this goal by visiting 5 new countries per year (y) for the next several years.

To Find :

Which inequality and solution shows the amount of years that it will take for Abraham to meet his goal.

Solution :

Let, after x years Abraham visited y countries.

It is mathematically given as :

$10 + 5x=y$

Now, it is given that his goal is minimum of 50 countries.

So,

$10+5x \ge 50\\\\5x\ge 40\\\\x \ge 8$

Therefore, minimum years required to meet his goals are 8.

Hence, this is the required solution.

4 0

3 years ago

Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li

Sophie [7]

Consider the closed region $V$ bounded simultaneously by the paraboloid and plane, jointly denoted $S$ . By the divergence theorem,

$\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV$

And since we have

$\nabla\cdot\mathbf f(x,y,z)=1$

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

$\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle2\pi\int_{r=0}^{r=1}r(3-r^2-2)\,\mathrm dr$
$=\dfrac\pi2$

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by $D$ , we have

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS$

Parameterize $D$ by

$\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k$
$\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k$

which would give a unit normal vector of $\mathbf k$ . However, the divergence theorem requires that the closed surface $S$ be oriented with outward-pointing normal vectors, which means we should instead use $\mathbf s_v\times\mathbf s_u=-u\,\mathbf k$ .

Now,

$\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du$
$=\displaystyle-4\pi\int_{u=0}^{u=1}u\,\mathrm du$
$=-2\pi$

So, the flux over the paraboloid alone is

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2$

6 0

3 years ago