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3 years ago

Find the parallelogram.

Mathematics

2 answers:

jek_recluse [69]3 years ago

8 0

Answer:

area - 120 cm

Step-by-step explanation:

madam [21]3 years ago

5 0

Answer:

A = 120 cm^2

P = 54 cm

Step-by-step explanation:

Area of parallelogram: = base * height

A = 15 cm * 8 cm = 120 cm^2

Perimeter of parallelogram = sum of lengths of sides

P = 15 cm + 15 cm + 12 cm + 12 cm = 54 cm

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QRST is a square. PQ = 2√ RU = 4<br> What is the length of SU? Round to the nearest tenth.

777dan777 [17]

Answer:

$SU=3.5\ units$

Step-by-step explanation:

step 1

In the isosceles right triangle PQT

PQ=PT ----> because is an isosceles triangle

Applying the Pythagoras Theorem

we have

$PQ=PT =\sqrt{2}\ units$

$QT^{2}=PQ^{2} +PT^{2}$

substitute the values

$QT^{2}=\sqrt{2}^{2} +\sqrt{2}^{2}$

$QT^{2}=4$

$QT=2\ units$

step 2

In the square QRST

$RS=QT=2\ units$

step 3

In the right triangle RSU

Applying the Pythagoras Theorem

$RU^{2}=RS^{2} +SU^{2}$

we have

$RU=4\ units$

$RS=2\ units$

substitute the values and solve for SU

$4^{2}=2^{2} +SU^{2}$

$SU^{2}=4^{2}-2^{2}$

$SU^{2}=12$

$SU=2\sqrt{3}\ units$

$SU=3.5\ units$

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mr_godi [17]

Length times width times height

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Read 2 more answers

Can some one explain how to do this?

Delvig [45]

Answer:

see explanation

Step-by-step explanation:

Using the tangent and sine ratios in the right triangle EFG

tan60° = $\frac{opposite}{adjacent}$ = $\frac{FG}{EG}$ = $\frac{28}{EG}$ ( multiply both sides by EG )

EG × tan60° = 28 ( divide both sides by tan60° )

EG = $\frac{28}{tan60}$ ≈ 16.2 in ( to the nearest tenth )

--------------------------------------------------------------

sin60° = $\frac{opposite}{hypotenuse}$ = $\frac{FG}{EF}$ = $\frac{28}{EF}$ ( multiply both sides by EF )

EF × sin60° = 28 ( divide both sides by sin60° )

EF = $\frac{28}{sin60}$ ≈ 32.3 in ( to the nearest tenth )

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3 years ago