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Georgia [21]
3 years ago
6

Please help!

Mathematics
1 answer:
Scrat [10]3 years ago
7 0

Answer:

  x = 0

Step-by-step explanation:

The argument x+3π/2 shifts the sine function 3π/2 to the left, making it equivalent to -cos(x). Then the equation becomes ...

  -2cos(x) = -2

  cos(x) = 1

On the interval [0, 2π), cos(x) is only 1 at x=0.

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Consider the equation 4x2 + 2x = (x + 2)(x − 5)x Match the Property used to create an equation with the same solution set. optio
mel-nik [20]

Factor then solve. Exact Form: x = 0 , 7 + √ 97 2 , 7 − √ 97 2 Decimal Form: x = 0 , 8.42442890 … , − 1.42442890 …

8 0
3 years ago
Find the measure for angle f<br><br> 46<br> 34<br> 122<br> 58
xxMikexx [17]

Answer:

\angle f = 122\degree

Step-by-step explanation:

\angle d = 58\degree (vertical angles)

\angle f+\angle d= 180\degree

(Interior angles on the same side of transversal)

\angle f+ 58\degree = 180\degree

\angle f = 180\degree-58\degree

\huge \orange {\boxed {\angle f = 122\degree}}

5 0
3 years ago
Coach Evans recorded the height, in inches of each player on his team. The results are shown.
marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile (Q_1)

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile (Q_3)

Terms in arranged in ascending order:

57,60,60,61,62,62,63,63,64

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

Q_1 is median of terms 57,60,60,61

Number of terms (n) = 4

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60

So, Q_1=60

So, 25% of the heights of a team is less than 60 inches

Q_3 is the median of terms 62,63,63,64

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63

So, Q_3=63

So, 75% of the heights of a team is less than 63 inches

Interquartile range = Q_3-Q_1=63-60=3

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0
3 years ago
What is 144/36 simplified?
NARA [144]
144/36 in lowest terms is 4.


To show my work, here.


1. Find the GCF of 144 and 36 so now we divide (144/36 = 4 and 36/36 is 1)

2. Now we have 4/1 so we simplify again so divide 4/1 and its 4
7 0
3 years ago
Solve the system of linear equations using elimination.
Vanyuwa [196]

Answer:

Step-by-step explanation:

A

8 0
3 years ago
Read 2 more answers
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