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miskamm [114]
3 years ago
7

Which sampling method divides the population up into​ sections, randomly selects some of those​ sections, then chooses all the m

embers from the selected sections to​ study? choose the correct answer below?
Mathematics
1 answer:
Advocard [28]3 years ago
3 0

Which sampling method divides the population up into​ sections, randomly selects some of those​ sections, then chooses all the members from the selected sections to​ study?

Answer: The above mentioned type of sampling is called cluster sampling.

Cluster sampling is a sampling technique in which the entire population of interest is divided into clusters or groups, then the investigator randomly selects some of these clusters and all the members of these randomly selected clusters are investigated.


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Please help asap 25 pts
allsm [11]

Answer:

There is no single answer to this question other than The first graph on the left is the answer. But you should read the explanation and memorize it.

Step-by-step explanation:

It's the first graph on the right. The points are always plotted (without exception) as (x value which means go along the x axis horizontally - left or right.), (y value which means to up (for a plus y) or down for a minus y. These facts are just memorized.

Summary

(x,y)

  • x goes either left or right.
  • x>0 goes right.  
  • x<0 goes left.
  • y goes up or down
  • y > 0 goes up
  • y < 0 goes down

Locations

First point (Please label this as first point)  - 3 (that goes left)  2 that goes up

You should be putting it in the upper left space.

Second Point. (-2,-2) that goes 2 to left and 2 down. You should put that point in the lower left space. There's only 1 point in the lower left space and that is this point.

Third Point (0,1) That's the only point on the y axis. It is above the x axis. It is all by itself on the y axis line. The other two points are done the same way. Please make sure you try them.


8 0
4 years ago
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Help really important
likoan [24]

Answer: Its c

Step-by-step explanation:

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8 0
2 years ago
Log(x-2)+log2=2logy<br>log(x-3y+3)=0​
In-s [12.5K]

Answer:

<h2>x = 4 and y = 2 or x = 10 and y = 4</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}\log(x-2)+\log2=2\log y&(1)\\\log(x-3y+3)=0&(2)\end{array}\right

===========================\\\text{DOMAIN:}\\\\x-2>0\to x>2\\y>0\\x-3y+3>0\to x-3y>-3\\=====================\\\\\text{We know:}\ \log_ab=c\iff a^c=b,\\\\\text{therefore}\ \log_ab=0\iff a^0=b\to b=1\\\\\text{From this we have}\\\\\log(x-3y+3)=0\iff x-3y+3=1\qquad\text{add}\ 3y\ \text{to both sides}\\\\x+3=3y+1\qquad\text{subtract 3 from both isdes}\\\\\boxed{x=3y-2}\qquad(*)\\\\\text{Substitute it to (1)}

\log(3y-2-2)+\log2=2\log(y)\qquad\text{use}\ \log_ab^n=n\log_ab\\\\\log(3y-4)+\log2=\log(y^2)\qquad\text{subtract}\ \log(y^2)\ \text{from both sides}\\\\\log(3y-4)+\log2-\log(y^2)=0\\\\\text{Use}\ \log_ab+\log_ac=\log_a(bc)\ \text{and}\ \log_ab-\log_ac=\log_a\dfrac{b}{c}\\\\\log\dfrac{(3y-4)(2)}{y^2}=0\qquad\text{use}\ \log_ab=0\Rightarrow b=1\\\\\dfrac{(3y-4)(2)}{y^2}=1\iff y^2=(3y-4)(2)\\\\\text{Use the distributive property}\ a(b+c)=ab+ac

y^2=(3y)(2)+(-4)(2)\\\\y^2=6y-8\qquad\text{subtract}\ 6y\ \text{from both sides}\\\\y^2-6y=-8\qquad\text{add 8 to both sides}\\\\y^2-6y+8=0\\\\y^2-2y-4y+8=0\\\\y(y-2)-4(y-2)=0\\\\(y-2)(y-4)=0\iff y-2=0\ \vee\ y-4=0\\\\\boxed{y=2\ \vee\ y=4}\in D

\text{Put the values of}\ y\ \text{to }\ (*):\\\\\text{for}\ y=2:\\\\x=3(2)-2\\\\x=6-2\\\\\boxed{x=4}\in D\\\\\text{for}\ y=4:\\\\x=3(4)-2\\\\x=12-2\\\\\boxed{x=10}\in D

4 0
3 years ago
How to divide polynomials
Bess [88]

Answer:

Step 1: Set up the synthetic division. ...

Step 2: Bring down the leading coefficient to the bottom row.

Step 3: Multiply c by the value just written on the bottom row. ...

Step 4: Add the column created in step 3.

Step-by-step explanation:

In algebra, polynomial long division is an algorithm for dividing a polynomial by another polynomial of the same or lower degree, a generalised version of the familiar arithmetic technique called long division. ... The result R = 0 occurs if and only if the polynomial A has B as a factor.

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3 years ago
What is the sum of (1-5q)+2(2.5q+8)
bogdanovich [222]

Answer:

17

Step-by-step explanation:

Eliminating parentheses, we have ...

... 1 - 5q +2·2.5q +2·8

... = 1 -5q +5q +16 . . . . . carry out the multiplication

... = q(-5+5) +(1 +16) . . . . group like terms

... = q·0 +17 . . . . . . . . . . . combine like terms

... = 17

8 0
3 years ago
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