Find three consecutive positive even integers such that 4 times the first decreased by the second is 12 more than twice the thir
d
1 answer:
Answer:
Step-by-step explanation:
n-2, n, n+2
4(n-2) - n = 12 + 2(n+2)
4 n - 8 - n - 12 - 2n - 4 = 0
n - 24 = 0
n = 24
22 , 24, 26
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