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Genrish500 [490]
3 years ago
7

Find three consecutive positive even integers such that 4 times the first decreased by the second is 12 more than twice the thir

d
Mathematics
1 answer:
Savatey [412]3 years ago
3 0

Answer:

Step-by-step explanation:

n-2, n, n+2

4(n-2) - n = 12 + 2(n+2)

4 n - 8 - n - 12 - 2n - 4 = 0

n - 24 = 0

n = 24

22 , 24, 26

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Fred has 45 books. Sally has 27 times more books than Fred. How many books does Sally have?
hodyreva [135]

Answer:

fred = 45 books

sally has 27 times more book than fred

sally = 45 X 27

= 1215 books

5 0
2 years ago
Jenna drew irregular quadrilateral ABCD inscribed in circle P. She knows that: m∠3=2⋅m∠1, and m∠2=2⋅m∠4, and m∠2+m∠3=360°. What
Mrrafil [7]

Answer:

The generalisation she can make from her work is that the other two angles of the quadrilateral are supplementary i.e their sum is 180°

Step-by-step explanation:

We are given the following from what she knows

m∠3=2⋅m∠1... 1

m∠2=2⋅m∠4 ... 2

m∠2+m∠3=360 ... 3

From what is given, we can substitute equation 1 and 2 into equation 3 as shown:

From 3:

m∠2+m∠3=360

Substituting 1 and 2 we will have:

2⋅m∠4 + 2⋅m∠1 = 360

Factor out 2 from the left hand side of the equation

2(m∠4+m∠1) = 360

Divide both sides by 2

2(m∠4+m∠1)/2 = 360/2

m∠4+m∠1 = 180°

Since the sum of two supplementary angles is 180°, hence the generalisation she can make from her work is that the other two angles of the quadrilateral are supplementary i.e their sum is 180°

7 0
2 years ago
Date whenever the following is true or false k+8>19, if k=11​
alexdok [17]

Answer:

The Answer is True

Step-by-step explanation:

k+8>19

k>19-8

k>11

4 0
3 years ago
Here’s the pic help please answer I’ll give brainliest !! It’s for a test
Fudgin [204]
A= -2

b=0

hope this helps
8 0
2 years ago
12^3 tanx-4^3tan2x<br>solve next step fast guys​
shepuryov [24]

Step-by-step explanation:

3 tan 2x - 4 tan 3x = tan² 3x * tan 2x

3 (tan 2x - tan 3x) = tan 3x + tan² 3x * tan 2x

= tan 3x (1 + tan 3x * tan 2x)

3 (tan 2x - tan 3x)/(1 + tan 3x * tan 2x) = tan 3x

3 * (- tan x) = tan 3x

-3tanx = (3 tan x - tan³ x) / (1 - 3 tan² x)

3 - tan² x = - 3 + 9 tan² x

tan x = + √3 /√5 or - √3/√5

4 0
3 years ago
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