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goldenfox [79]
3 years ago
5

How many moles of h are in 0.73 mole of c6h10s

Chemistry
1 answer:
Mnenie [13.5K]3 years ago
7 0

Answer:

7.3 mole

Explanation:

1 C6H10S gives 10H

0.73 mole of C6H10S gives X mole of Hydrogen

X= 0.73×10=7.3mole

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GenaCL600 [577]

what?? please reword this

6 0
3 years ago
List the subshells that hold the 25 electrons in a<br> manganese atom in order of increasing energy
jonny [76]

Answer:

1s2 2s2 2p6 3s2 3p6 4s2 3d5

Explanation:

According to the Aufbau principle, electrons are filled in orbitals in order of increasing energy. The energy of orbitals in the electronic configuration of manganese increases from left to right, hence 3d orbital is much greater in energy than a 3p orbital.

The arrangement of orbitals in order of increasing energy is shown in the answer above.

4 0
3 years ago
A typical virus is 5x10-6 cm in diameter. if avogadro's number of these virus particles were laid in a row, how many kilometers
Debora [2.8K]
Answer is: line be long 3,011·10¹³ kilometers.
diametar of virus = 5·10⁻⁶ cm ÷ 100000 = 5·10⁻¹¹ km.
line lenght = 5·10⁻¹¹ km · 6,023·10²³.
line lenght = 3,011·10¹³ km.
Avogadro number = 6,023·10²³.
1 cm = 10⁻² m = 10⁻⁵ km.
8 0
3 years ago
Read 2 more answers
Wet steam at 1100 kPa expands at constant enthalpy (as in a throttling process) to 101.33 kPa, where its temperature is 105°C. W
nikklg [1K]

Answer:

There are 3 steps of this problem.

Explanation:

Step 1.

Wet steam at 1100 kPa expands at constant enthalpy to 101.33 kPa, where its temperature is 105°C.

Step 2.

Enthalpy of saturated liquid Haq = 781.124 J/g

Enthalpy of saturated vapour Hvap = 2779.7 J/g

Enthalpy of steam at 101.33 kPa and 105°C is H2= 2686.1 J/g

Step 3.

In constant enthalpy process, H1=H2 which means inlet enthalpy is equal to outlet enthalpy

So, H1=H2

     H2= (1-x)Haq+XHvap.........1

    Putting the values in 1

    2686.1(J/g) = {(1-x)x 781.124(J/g)} + {X x 2779.7 (J/g)}

                        = 781.124 (J/g) - x781.124 (J/g) = x2779.7 (J/g)

1904.976 (J/g) = x1998.576 (J/g)

                     x = 1904.976 (J/g)/1998.576 (J/g)

                     x = 0.953

So, the quality of the wet steam is 0.953

                   

7 0
3 years ago
Read 2 more answers
Three quantum numbers for an electron in a hydrogen atom in a certain state are
OLga [1]
It is option A 4s cause n=4, l=1 this is 4s orbital
6 0
3 years ago
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