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GarryVolchara [31]
3 years ago
13

Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points.

Chemistry
1 answer:
OverLord2011 [107]3 years ago
7 0
The freezing point depression is a colligative property, which means that it depends on the number of particles of solute disolved in the solution.

When you have solutes that are ionic compounds they dissociate in water into ions, then the compound that dissociates more ions will produce more particles and will decrease the freezing point the most.

Given theses aqueous solutions Na2 CO3, Co Cl3, and Li NO3 you can predict the order of the freezing points.

First, write the dissociation equations>

Na2CO3 -> 2Na(+) + CO3 (2-)  These are 3 ions: two of Na(+) and one of CO3(2-)

The number inside parenthesis are number of charge not number of molecules.

Co Cl3 -> Co(3+) + 3 Cl (1-) Those are 4 ions: one of Co (+) and three of Cl (-)

Li NO3 -> Li (+) + NO3 (-) those are two ions: one of Li (+) and one of NO3(-)

Then the ionic compound that dissociates into more ions give the solution with lower freezing point, and these is the rank from higher to lower freezing point:

Li NO3 > Na2 CO3 > Co Cl3.
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A 3 L pocket of air at sea level has a pressure of 100 atm. Suppose the air pockets rise in the atmosphere to a certain height a
liraira [26]

Answer:

30 atm

Explanation:

Initial Volume, V1 = 3L

Initial Pressure, P1 = 100 atm

Final Volume V2 = 10 L

Final Pressure, P2 = ?

These quantities are related by the Boyle's law equation which is given as;

V1P1 = V2P2

P2 = V1 * P1  /  V2

P2 = 3 * 100 / 10

P2 = 30 atm

5 0
2 years ago
A certain substance X has a normal freezing point of -10.1 degree C and a molal freezing point depression constant K_f = 5.32 de
kirill115 [55]

Answer: -15.4^00C

Explanation:

T^0_f-T_f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}

where,

T_f = boiling point of solution = ?

T^o_f = boiling point of solvent (X) = -10.1^oC

k_f = freezing point constant  = 5.32^oC/kgmol

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte like urea)

= mass of solute (urea) = 29.82 g

= mass of solvent (X) = 500.0 g

M_2 = molar mass of solute (urea) = 60 g/mol

Now put all the given values in the above formula, we get:

(-10.1-(T_f))^oC=1\times (5.32^oC/m)\times \frac{(29.82g)\times 1000}{60\times (500.0g)}

T_f=-15.4^0C

Therefore, the freezing point of  solution is -15.4^0C

7 0
2 years ago
Which one of Newton's Laws fits this statement: More mass means more force needed to accelerate?
ivolga24 [154]

Answer:

Newton's Second Law

Explanation:

Newton's second law basically states that the acceleration of a body which is produced by a net force is directly proportional to the magnitude of net force applied in the same direction.

This tells us that

     F   is directly proportional to a

⇒ F= ma

So we can also state from the above equation, that when we have more mass, we need more net force to accelerate it. Here, we are keeping the acceleration constant so we can surely say that force and mass varies directly.

Therefore, we have made good use of Newton's Second Law of motion to arrive at this conclusion.

4 0
3 years ago
1. A 25 g rock is placed in a graduated cylinder with water. The volume of the liquid rises from 18.3 mL to 21.4 mL Calculate th
MaRussiya [10]

Answer:

1. \rho=8.06g/cm^3

2. H=10cm

Explanation:

Hello,

1. In this case, since the volume of the rock is obtained via the difference between the volume of the cylinder with the water and the rock and the volume of the cylinder with the water only:

V=21.4mL-18.3mL=3.1mL

Thus, the density turns out:

\rho=\frac{m}{V}=\frac{25g}{3.1cm^3}  \\\\\rho=8.06g/cm^3

2. In this case, given the density and mass of aluminum we can compute its volume as follows:

V=\frac{m}{\rho}=\frac{1080g}{2.7g/cm^3}=400cm^3

Moreover, as the volume is also defined in terms of width, height and length:

V=W*H*L

The height is computed to be:

H=\frac{V}{L*W}=\frac{400cm^3}{5cm*8cm}\\ \\H=10cm

Best regards.

3 0
3 years ago
Qué tipo de reacciones pertenecen las combustiones?
navik [9.2K]

Answer:

Si una reacción química libera energía, se llama reacción exotérmica. El ejemplo más común es la combustión, en la cual la energía se manifiesta en forma de calor y luz. Si, por el contrario, la reacción química requiere energía del medio para efectuarse, recibe el nombre de reacción endotérmica.

5 0
2 years ago
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