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aleksandr82 [10.1K]
3 years ago
11

Five oranges were selected at random from a crate of 53 oranges. Their diameters were measured, in millimeters, and then recorde

d. Diameters: 46, 39, 53, 61, 49 What is the estimated mean diameter of the 53 oranges in the crate?
Mathematics
2 answers:
lina2011 [118]3 years ago
8 0
The answer would be 50 I assume? To find the mean, or the average, you add all of the data values together, take the sum and divide it by the number of values in the data set (5). The quotient of the division problem will be the mean diameter of the oranges, yet we still have to round it. So if we round this answer to the nearest one, the answer would be 50! Hope this helped :)!
Olin [163]3 years ago
5 0
Ok so mean means average so exmple
mean of 1,2,3+5 would be (1+2+3+5)/4
(sum of terms)/(number of terms)=mean so

number of terms=5 since 5 oranges
sum=(46+39+53+61+49)

so mean=(46+39+53+61+49)/5=248/5=49.6

so the answer would be 49.6 (estimateed to be 50)
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Answer:

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7 0
3 years ago
Please help!!!!!
vampirchik [111]

Answer:

Step-by-step explanation:

Consider the quadratic equation, we have

ax^2+bx+c=0

Dividing the equation by a, we get

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Put \frac{c}{a} on the other side,

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Add (\frac{b}{2a})^2 on both the sides,

x^2+\frac{b}{a}x+(\frac{b}{2a})^2=\frac{-c}{a}+(\frac{b}{2a})^2

completing the square, we have

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Now, solving for x,

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8 0
4 years ago
Read 2 more answers
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