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aleksandr82 [10.1K]
3 years ago
11

Five oranges were selected at random from a crate of 53 oranges. Their diameters were measured, in millimeters, and then recorde

d. Diameters: 46, 39, 53, 61, 49 What is the estimated mean diameter of the 53 oranges in the crate?
Mathematics
2 answers:
lina2011 [118]3 years ago
8 0
The answer would be 50 I assume? To find the mean, or the average, you add all of the data values together, take the sum and divide it by the number of values in the data set (5). The quotient of the division problem will be the mean diameter of the oranges, yet we still have to round it. So if we round this answer to the nearest one, the answer would be 50! Hope this helped :)!
Olin [163]3 years ago
5 0
Ok so mean means average so exmple
mean of 1,2,3+5 would be (1+2+3+5)/4
(sum of terms)/(number of terms)=mean so

number of terms=5 since 5 oranges
sum=(46+39+53+61+49)

so mean=(46+39+53+61+49)/5=248/5=49.6

so the answer would be 49.6 (estimateed to be 50)
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Rom4ik [11]
I am not sure if what I am about to explain is correct but I hope it is somewhere along the correct path

To solve the problem use the following steps below....

Step 1: Take your numbers and place them in parentheses

(4-1/6)

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6/6=1
6/6x4=24/6

Step 3: Place your new fraction back into the problem

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Step 4: Use the operation,subtraction, and minus 1/6 from 24/6

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Step 5(is optional): Turn 23/6 into a mixed fraction by dividing 23 by 6

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Step 6(is optional): put your answer into a final statement

(4-1/6)=23/6=3 5/6

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I hope this helps and I apologize in advance if any false information was given.
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3 years ago
Please answer correctly !!!! Will mark brainliest !!!!!!!!
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Answer:

A

Step-by-step explanation:

Notice how it points it out for the x coordinate, and the closed circle means that point is included, So it's the range of the smallest x coordinate to the greatest x coordinate.

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