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2 years ago

Find part "b". (fillertextfillertextfillertext)

Mathematics

2 answers:

mr_godi [17]2 years ago

6 0

Umm...is there more information you can give me in order to solve this problem...lol there isn't enough information

vesna_86 [32]2 years ago

4 0

Answer:

https://rimsd.owschools.com/media/g_geo_2015/5/01.gif

Step-by-step explanation:

this is the image for the problem

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Violet is planning to make 32 semiannual loan payments of $1580 dollars each. If her bank charges an annual interest rate of 3.8

sergij07 [2.7K]

Answer:

$21,623.70

Step-by-step explanation:

A suitable financial calculator can compute the beginning balance and the remaining balance for you. The attachments show a TI-Nspire calculator's TVM solver app being used to answer this question.

The first attachment shows the computation of the loan value. It is about $37,624.54.

The second attachment shows the computation of the remaining balance after 16 of the 32 semi-annual payments have been made.

The loan balance 8 years from the end of the loan will be about $21,623.70.

8 0

2 years ago

HELP PLLSS<br> 92;69<br> work included!

Nata [24]

Answer:

92/69 cannot be simplified

Step-by-step explanation:

8 0

3 years ago

List all the factor pairs for 48. make a table to help and add the table.

Feliz [49]

Answer:

The factor pairs of the number 48 are: 1 x 48, 2 x 24, 3 x 16, 4 x 12, and 6 x 8

Step-by-step explanation:

7 0

3 years ago

x^2-y=7 and y-5x=-11 The system of equations above has two solutions. The solution in Quadrant 1 is (A,B) and the solution in Qu

dimaraw [331]

By solving the system of equations, we can see that the solutions are:

(A, B) = (4, 9)

(C, D) = (1, -6).

<h3>How to solve the system of equations?</h3>

Here we have the following system of equations:

x^2 - y = 7

y - 5x = -11

If we isolate the variable y in both equations, we get:

y = x^2 - 7

y = -11 + 5x

Now we can equate these two to get:

x^2 - 7 = -11 + 5x

now we have a quadratic equation, this can be rewritten as:

x^2 - 7 + 11 - 5x = 0

x^2 - 5x + 4 = 0

Using the quadratic formula, we will see that the solutions are:

$x = \frac{5 \pm \sqrt{(-5)^2 - 4*1*(4)} }{2*1}$

Solving that we get:

$x = \frac{5 \pm \sqrt{(9} }{2} \\\\x = \frac{5 \pm 3}{2}$

So the two solutions for x are:

x = (5 + 3)/2 = 4

x = (5 - 3)/2 = 1

Evaluating the second equation in these x-values we get:

y = -11 + 5*4 = -11 + 20 = 9

y = -11 + 5*1 = -6

Then we have the coordinate pairs: (4, 9) (on the first quadrant) and (1, -6) on the fourth quadrant.

Learn more about systems of equations:

brainly.com/question/13729904

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8 0

1 year ago

(2a^(3))^(-3)<br> --------<br> (3b(-2))

Andrei [34K]

Hello,

$\dfrac{(2a^{3})^{-3}}{3b*(-2)}=-\dfrac{1}{(2a^3)^3*6b}=-\dfrac{1}{48a^9b}$

7 0

2 years ago