The equation representing the solubility of
:

Test tube of ammonium chloride (NH4Cl) being heated over a bunsen burner flame. Ammonium chloride decomposes readily when heated, but condenses in the cooler area at the top of the test tube. This is a reversible reaction, where the ammonium chloride decomposes into the gases ammonia (NH3) and hydrogen chloride (HCl).
None of the above I believe it is what can form a tornado??
Answer:
C5H7N
C10H14N2
Explanation:
ok so lets lay out this nicely
elements C H N
percentage 74 8.7 17.3
mass number 12 1 14
divided percentage by mass 6.167 8.7 1.2357
now divide the smallest number with the 4.99 7.04 1
rest for instance 1,237 is the smallest.
so 6.167÷1,237
and 8.7 ÷1.237
and 1,237 divide 1.237
now the ratio is C5H7N
now for molecular formula find Mr of C5H7N which is (12×5)+7+14=81
next divide 162.1÷81=2
so now for molecular formula just multipily everythng by 2
C10H14N2
Answer:
Assuming that all of the oxygen is used up, 1.53×4111.53×411 or 0.556 moles of C2H3Br3 are required. Because there are only 0.286 moles of C2H3Br3 available, C2H3Br3 is the limiting reagent.
Limiting Reagent What is the limiting reagent if 76.4 grams of C2H3Br3 were reacted with 49.1 grams of O2? C2H3Br3 + 11O2 → 8CO2 + 6H2O + 6Br2 SOLUTION Using Approach 1: A. 76.4g × (1 mol/ 266.72 g) = 0.286 moles C2H3Br3 49.1g × (1 mole/ 32 g) = 1.53 moles O2 B.
Explanation:
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https://chem.libretexts.org/Bookshelves/Introductory_Chemistry/Map%3A_Introductory_Chemistry_(Tro)/08%3A_Quantities_in_Chemical_Reactions/8.04%3A_Limiting_Reactant_and_Theoretical_Yield