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balandron [24]
3 years ago
10

A glass breaks is a physical or chemical change

Chemistry
2 answers:
maksim [4K]3 years ago
7 0

Breaking glass is an example of a physical change because if you break it, it is still glass.

Licemer1 [7]3 years ago
3 0

physical.......................................................

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When molybdate (MoO3) and Zinc (Zn) are heated together they react in this equation:
schepotkina [342]

Answer: The mole ratio of Zn to ZnO is 3: 3.

Explanation:

According to law of conservation of mass, mass can be neither be created nor be destroyed. The mass on reactant side must be equal to the mass on product side. Thus the atoms of each element on both side of the reaction must be same.

The balanced chemical reaction is:

3Zn+2MoO_3\rightarrow Mo_2O_3+3ZnO

Here 3 moles of Zn combine with 2 moles of MoO_3 to give 1 mole of Mo_2O_3 and 3 moles of ZnO. Thus the mole ratio of Zn to ZnO is 3: 3.

5 0
3 years ago
Hg(OH)2+H3PO4=Hg3(PO4)2+H2O
Papessa [141]
What about them?.....
6 0
3 years ago
PLS HELP
Juli2301 [7.4K]

Answer:

False

Explanation:

Water molecules are spread up but slightly, enough that none of the molecules actually move freely around each other. Only gas and plasma molecules are very spread apart.

7 0
2 years ago
A rectangular prism of volume 84 cm 3 has a mass of 760 g. What is the density of the rectangular prism? 5.8 g•cm 3 9.0 g/cm 3 6
Fiesta28 [93]

Answer:

9.0 g/cm³

Explanation:

Density can be computed with the formula:

D=\dfrac{M}{V}

Where:

D = Density

M = Mass

V = Volume

In your problem we are given:

84 cm³ = volume

760 g = mass

So we just plug in our given into the formula:

D=\dfrac{M}{V}

D=\dfrac{760g}{84cm^{3}}

D=9.05g/cm^{3}

The answer would then be:

9.0 g/cm³

3 0
3 years ago
What is the ph of 0.450 m al(no3)3 [ka for al3+(aq) = 1.00x10-5]? express your answer to two decimal places?
White raven [17]

Answer : The pH of the solution is, 2.67

Explanation :

The equilibrium chemical reaction is:

                           Al^{3+}+H_2O\rightarrow Al(OH)^{2+}+H^+

Initial conc.       0.450                   0               0

At eqm.           (0.450-x)                 x               x

As we are given:

K_a=1.00\times 10^{-5}

The expression for equilibrium constant is:

K_a=\frac{(x)\times (x)}{(0.450-x)}

Now put all the given values in this expression, we get:

1.00\times 10^{-5}=\frac{(x)\times (x)}{(0.450-x)}

x=0.00212M

The concentration of H^+ = x = 0.00212 M

Now we have to calculate the pH of solution.

pH=-\log [H^+]

pH=-\log (0.00212)

pH=2.67

Therefore, the pH of the solution is, 2.67

8 0
3 years ago
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