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nirvana33 [79]
1 year ago
15

A sample of a compound made entirely from copper and oxygen was found to have a total mass of 0.143 g the mass of copper in the

compound was found to be 0.1271 g calculate the mass of oxygen in the same. Also, Calculate the number of moles of oxygen in the sample. Please help!! Thank you in advance.
Chemistry
1 answer:
tensa zangetsu [6.8K]1 year ago
6 0

Mass of Oxygen: 0.0159 grams

Moles of Oxygen: 9.94x10^-4

To find the mass of oxygen, subtract the mass of copper from the total mass.

0.143-0.1271=0.0159

There are 0.0159 grams of Oxygen.

To find how many moles there are, divide the given amount of oxygen by the molar mass (atomic mass) of oxygen because that mass is the same as one mole of oxygen.

Molar mass of Oxygen: 16.00

0.0159/16.00=9.94*10^{-4}

There are 9.94*10^-4 moles of Oxygen.

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In which location would an ocean ridge most likely be located
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3 years ago
How many moles of Chromium are in 1.410 * 10 ^ 23 atoms of Chromium?
leva [86]

Answer:

<h3>The answer is 0.23 moles</h3>

Explanation:

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n =  \frac{N}{L}  \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{1.410 \times  {10}^{23} }{6.02 \times  {10}^{23} }  \\  = 0.234219...

We have the final answer as

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4 0
3 years ago
A sample of an unknown biochemical compound is found to have a percent composition of 45.46 percent carbon, 7.63 percent hydroge
Leona [35]

Answer:

Formular = C₅H₁₁NO₃

Explanation:

The empirical formular is the simplest formular of a compound can have.

We use the steps below to obtain the empirical formular;

Step 1: Obtain the mass of each element present in grams. Element % = mass in g = m.

Carbon = 45.46% = 45.46g

Hydrogen = 7.63% = 7.63g

Nitrogen = 10% = 10g

Oxygen = 100% - (45.46% + 7.63% + 10%) = 36.31% = 36.31g

Step 2: Determine the number of moles of each type of atom present.

Molar amount (M) = m/atomic mass

Carbon = 45.46 / 12 = 3.7883

Hydrogen = 7.63 / 1 = 7.63

Nitrogen = 10 / 14 = 0.7143

Oxygen = 36.91 / 16 = 2.3069

Step 3: Divide the number of moles of each element by the smallest number of moles. Smallest = 0.7143

Carbon = 3.7883 / 0.7143 = 5.3035

Hydrogen = 7.63 / 0.7143 = 10.67

Nitrogen =  0.7143 / 0.7143 = 1

Oxygen = 2.2693 / 0.7143 = 3.1770

Step 4: Convert numbers to whole numbers

Carbon = 5

Hydrogen = 11

Nitrogen = 1

Oxygen = 3

Formular = C₅H₁₁NO₃

3 0
4 years ago
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