Answer:
0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.
Explanation:
Mass percentage of oxalic acid = 5.50%
This means that in 100 grams of solution there are 5.50 grams of oxalic acid.
Mass of solution , m = 100
Volume of the solution = V
Density of the solution = d = 1.024 g/mL
V = 97.66 mL = 0.09766 L
(1 mL = 0.001 L)
Moles of oxalic acid = 
The molarity of the solution :
0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.
Answer:
Its B
Explanation:
Products <=> reactants; products can go back to reactant and reactants can form products, depending on the equilibrium position.
The equilibrium position, if it is on the left, and much of the product is formed. If the equilibrium position is not the right, then its the vice versa The equilibrium position is determined by ;
- <em><u>Temperature</u></em>
If the reaction is endothermic, it will be favoured by increase in temperature and equilibrium position will shift to the right ( reactants )
If the reaction is exothermic, its the vice versa
<em><u>N</u></em><em><u>O</u></em><em><u>T</u></em><em><u>E</u></em><em><u>:</u></em><em><u> </u></em>Only temperature affects the equilibrium position
43 degrees
angle of reflection is equal to the angle of incidence
# An alkaline compound
# High melting and boiling point
Answer: 12.5 mg
Explanation:
The half-life of Iodine -123 is 13 hours.
Between 8 am on Monday and 10 am on Tuesday will be 26 hours.
After the first 13 hours, the Iodine should be left with half of its initial quantity
= 50/2
= 25 mg
There are now 13 hours remaining meaning that the Iodine will be half of the 25mg after that period.
= 25/2
= 12.5 mg.
12.5 mg remain at 10 am the next day.
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