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Nataly [62]
3 years ago
12

Which planet has a storm called the Great Dark Spot swirling in its atmosphere?

Physics
2 answers:
vesna_86 [32]3 years ago
5 0

The answer is Jupiter not neptune :)

Viktor [21]3 years ago
3 0
Im thinking D. Neptune..
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Naturally occurring element x exists in three isotopic forms: x-28 (27.977 amu, 92.23% abundance), x-29 (28.976 amu, 4.67% abund
Bond [772]

To solve for the weighted average atomic weight of X, all we have to do is to calculate for the contribution of each isotope. The contribution of each isotope on the atomic weight of x is calculated by multiplying their respective atomic weights with the abundance, therefore:

X – 28 = 27.977 amu * (92.23 / 100)

X – 28 = 25.803 amu

 

X – 29 = 28.976 amu * (4.67 / 100)

X – 29 = 1.353 amu

 

X – 30 = 29.974 amu * (3.10 / 100)

X – 30 = 0.929 amu

 

Hence:

X = X – 28 + X – 29 + X – 30

X = 25.803 amu + 1.353 amu + 0.929 amu

<span>X = 28.085 amu</span>

6 0
3 years ago
How are velocity and displacement related?
Keith_Richards [23]

Velocity is the rate at which displacement changes with time. It is a vector, too. The average velocity over some interval is the total displacement during that interval, divided by the time. ... Speed is a scalar, which describes the total distance travelled by some object during some time interval. Plze mark me brainiest

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3 years ago
Consider a car moving at a constant velocity. Recall that, for any object to move at a constant velocity, the net force acting o
Eddi Din [679]

For any object to move at a constant velocity, the net force acting on the object must be ZERO.

6 0
3 years ago
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1. Calculate the total heat content of 10 kg of ice at -23°C.?
vesna_86 [32]

To solve the problem, we must know the heat capacity of ice and water.

For Cp = 2090 J/kg C

H = mCpT

H = (10 kg) ( 2090 J/ Kg C) ( -23 C)

H = - 480700 J

For water Cp = 4180 j/kg C

H = (100 kg) ( 4180 J/kg C) ( 60 C)

<span>H = 2508000 J</span>

8 0
3 years ago
A rock hits a window and stops in 0.15 seconds. The net force on the rock is 58N during the collision. What is the magnitude of
nlexa [21]

Answer:

The change in momentum is  \Delta p =   0.7 \ kg\cdot m \cdot s^{-1}

Explanation:

From the question we are told that

    The time taken for the stone to stop is \Delta  t = 0.15 \ seconds

    The net force on the rock is  F =  58 \ N

   

The impulse of the rock can be mathematically represented as

     I  =  F * \Delta t

Substituting values

     I  =  58 * 0.15

    I  =  0.7\  kg * m  * s^{-1}

Now impulse is defined as  the rate at which momentum change

   Hence the change in momentum \Delta p  of the rock is equal to the impulse of the rock

 So  

       \Delta p =  I  =  0.7 \ kg\cdot m \cdot s^{-1}

7 0
3 years ago
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