Find the work done in moving a particle from p to q if the magnitude and direction
1 answer:
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Answer:
The work required is -515,872.5 J
Explanation:
Work is defined in physics as the force that is applied to a body to move it from one point to another.
The total work W done on an object to move from one position A to another B is equal to the change in the kinetic energy of the object. That is, work is also defined as the change in the kinetic energy of an object.
Kinetic energy (Ec) depends on the mass and speed of the body. This energy is calculated by the expression:
where kinetic energy is measured in Joules (J), mass in kilograms (kg), and velocity in meters per second (m/s).
The work (W) of this force is equal to the difference between the final value and the initial value of the kinetic energy of the particle:
In this case:
- W=?
- m= 2,145 kg
- v2= 12
- v1= 25
Replacing:
W= -515,872.5 J
<u><em>The work required is -515,872.5 J</em></u>
Answer:
Explanation:
The energy of a photon is given by the equation , where h is the <em>Planck constant</em> and f the frequency of the photon. Thus, N photons of frequency f will give an energy of
.
We also know that frequency and wavelength are related by , so we have
, where c is the <em>speed of light</em>.
We will want the number of photons, so we can write
We need to know then how much energy do we have to calculate N. The equation of power is , so for the power we have and considering 1 second we can calculate the total energy, and then only consider the 4% of it which will produce light, or better said, the N photons, which means it will be
.
Putting this paragraph in equations:
.
And then we can substitute everything in our equation for number of photons, in S.I. and getting the values of constants from tables:
Answer:
In order of increasing wavelength, the answer is:
(i) The gamma rays produced by a radioactive nuclide used in medical imaging
(iv) The yellow light from sodium-vapor streetlights
(v) The red light of a light emitting diode, such as in a calculator display
(ii) Radiation from an FM radio station at 93.1 MHz on the dial
(iii) A radio signal from an AM radio station at 680kHz on the dial
Explanation:
First, you have to know that the wavelength of a sinusoidal wave traveling at a constant speed is given by:
λ
Where λ is the wavelength, is the constant speed and
is the wave's frequency. In the case of electromagnetic radiation in free space, the constant speed is the speed of light.
From explained above, you can conclude that there is a proportionality relationship between the wavelength and the frequency, they are inversely proportional. That means: the highest frequency will have the shortest wavelength and vice-versa.
So, you have the following types:
(i) The gamma rays produced by a radioactive nuclide used in medical imaging
Frequency : Typically greater than Hz
(ii) Radiation from an FM radio station at 93.1 MHz on the dial
Frequency: 93.1 MHz
(iii) A radio signal from an AM radio station at 680 kHz on the dial
Frequency: 680 kHz
(iv) The yellow light from sodium-vapor streetlights
Frequency: Visible spectrum of approx. 508 - 526 THz
(v) The red light of a light-emitting diode, such as in a calculator display
Frequency: Visible spectrum of approx. 400 - 484 THz
Then, you have to organize them from the highest frequency to the smallest one (decreasing frequency), and as the highest frequency will have the shortest wavelength, you are going to have it organized in an increasing wavelength mode.
Then in order of increasing wavelength, the answer will be:
(i) , (iv), (v), (ii), (iii)