A. The Dawes limit tells
us that the resolving power is equal to 11.6 / d, where d is the diameter of
the eye’s pupil in units of centimeters. The eye's pupil can dialate to approximately
7 mm, or 0.7 cm. So 11.6 / .7 = 16.5 arc seconds, or about a quarter arc
minute ~ 17 arc seconds<span>
Although, the standard answer for what people can really see
is about 1 arc minute.
</span>
<span>
B. It is considered as linear, so given a 10 meter telescope
(10,000 mm): </span>
10000 / 7 = 1428 times
better for the 10 meter scope ~ 1400 times better (in 2 significant figures)
<span>
<span>C. For a 7 cm interferometer, that is just similar to a 7 cm
scope. Therefore we would expect </span></span>
<span><span>11.6 / 7 = 1.65 arc seconds ~ 1.7 arc seconds</span></span>
<span><span>T</span></span>his value is what
we typically can get from a 7 cm scope.
When I drive to the office, I drive through two school zones,
and four intersections that are controlled by traffic lights.
My average speed for the trip is higher than my instantaneous
speed is at any point in the school zones, or at any time when
I'm waiting for a red light to change.
Responder: 480 vatios
Explicación:
La potencia en un circuito eléctrico am puede expresarse como el producto si la corriente y el voltaje en el circuito.
Potencia = corriente × voltaje
Corriente dada = 4 amperios
Voltaje = 120 voltios
Potencia gastada en el circuito = 4 × 120
Potencia gastada en el circuito =
480 vatios
Answer:
Here we need to make parallel connection of two 80 ohm resistors to achieve 40 ohm net resistance.
Explanation:
As we know that the resistances in series add up directly and here we are given with only the resistors of 80 Ω.
So when we connect two resistors of 80 ohm in parallel we get the resultant of 40 ohm.
Mathematically:
gives us the only combination of two resistors in parallel.
Answer:
A drunk driver's car travel 49.13 ft further than a sober driver's car, before it hits the brakes
Explanation:
Distance covered by the car after application of brakes, until it stops can be found by using 3rd equation of motion:
2as = Vf² - Vi²
s = (Vf² - Vi²)/2a
where,
Vf = Final Velocity of Car = 0 mi/h
Vi = Initial Velocity of Car = 50 mi/h
a = deceleration of car
s = distance covered
Vf, Vi and a for both drivers is same as per the question. Therefore, distance covered by both car after application of brakes will also be same.
So, the difference in distance covered occurs before application of brakes during response time. Since, the car is in uniform speed before applying brakes. Therefore, following equation shall be used:
s = vt
FOR SOBER DRIVER:
v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s
t = 0.33 s
s = s₁
Therefore,
s₁ = (73.33 ft/s)(0.33 s)
s₁ = 24.2 ft
FOR DRUNK DRIVER:
v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s
t = 1 s
s = s₂
Therefore,
s₂ = (73.33 ft/s)(1 s)
s₂ = 73.33 ft
Now, the distance traveled by drunk driver's car further than sober driver's car is given by:
ΔS = s₂ - s₁
ΔS = 73.33 ft - 24.2 ft
<u>ΔS = 49.13 ft</u>
