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3 years ago

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What does resonance result in? Quieter sounds, frequency, amplitude

2 answers:

Amanda [17]3 years ago

6 0

Answer:

The answer is louder sounds. Resonance is the process, in which a system vibrates with increasing amplitudes, at specific frequencies of excitation. Resonance results in louder sounds. ... This is because of the surrounding environment, resonates with the cavity of the shell .

Explanation:

Tpy6a [65]3 years ago

4 0

<u>Question: </u>

What does resonance result in?

A) Quieter sounds B) frequency, C) amplitude D) Louder sounds.

<u>Answer: </u>

Resonance results in louder sounds.

<u>Explanation: </u>

In fact, the point at which the sound show maximum amplitude is termed as resonance. Since there is an increase in amplitude, the sound turns louder, and louder. Resonance is the situation, where one body vibrates after being effected by another vibrating body. Let us take an example of two bodies ‘A’ and ‘B’ at vibration.

Let the body A is in vibration at a particular frequency. And then, let the body ‘B’ disturbs with its vibration. Now, ‘A’ imparts some additional frequency, from ‘B’, which leads to resonance. So, if the amplitude increases, the sound produced is huge, and hence louder.

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A 5 kg block is being pushed horizontally across a level surface at a constant velocity. What is the magnitude of the Normal for

luda_lava [24]

Answer:

50 N.

Explanation:

On top of a horizontal surface, the normal force acting on an object is equivalent to the force of gravity acting on the object. That is:

$\displaystyle \begin{aligned} F_N = F_g & = ma \\ & = mg\end{aligned}$

The mass of the block is 5 kg and the given force due to gravity is 10 N/kg. Substitute and evaluate:

$\displaystyle F_N = F_g = (5\text{ kg})(10 \text{ N/kg}) = 50 \text{ N}$

In conclusion, the normal force acting on the block is 50 N.

5 0

2 years ago

A) An automobile light has a 1.0-A current when it is connected to a 12-V battery. Determine the resistance of the light.

kirill [66]

Answer:

The resistance in first case is 12 Ω, power delivered is 12 W, and potential difference is 0.01 V

Explanation:

Given:

(A)

Current $I = 1$ A

Voltage $V = 12$ V

For finding the resistance,

$V = IR$

$R = \frac{V}{I}$

$R = \frac{12}{1}$

$R =$ 12Ω

(B)

For finding power delivered,

$P = I^{2} R$

$P = (1) ^{2} \times 12$

$P = 12$ Watt

(C)

For finding the potential difference,

$V = IR$

$V = 5 \times 10^{-3} \times 2$

$V = 10 \times 10^{-3}$

$V = 0.01$ V

Therefore, the resistance in first case is 12 Ω, power delivered is 12 W, and potential difference is 0.01 V

4 0

3 years ago

A small button placed on a horizontal rotating platform with diameter 0.320 m will revolve with the platform when it is brought

Otrada [13]

Answer:

0.2687 approximately 0.27

Explanation:

Diameter = 0.320

Speed = 40.0 rev/min

We are required to find coefficient of static friction between friction and button

The radius can be calculated as

0.320/2

= 0.160m

Then we have the rotational speed w = 40rev/min x 2pi/60

= 4.19 rad/s

umg = mrw²

u = mrw²/mg

u = rw²/g -------(1)

g = 9.8

When we put values into equation 1

0.150m x 4.19² / 9.8

= 0.150m x 17.5561 /9.8

= 0.2689

This is approximately 0.27

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2 years ago

A child looks at his reflection in a spherical Christmas tree ornament 8.0 cm in diameter in season that the image of his face i

malfutka [58]

From the information given,

diameter of ornament = 8

radius = diameter/2 = 8/2

radius of curvature, r = 4

Recall,

focal length, f = radius of curvature/2 = 4/2

f = 2

Recall,

magnification = image d

8 0

1 year ago

This table shows four examples of experiments.

yarga [219]

Answer

32000

Explanation:

120394

5 0

2 years ago

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