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4 years ago

What does resonance result in? Quieter sounds, frequency, amplitude

Physics

2 answers:

Amanda [17]4 years ago

6 0

Answer:

The answer is louder sounds. Resonance is the process, in which a system vibrates with increasing amplitudes, at specific frequencies of excitation. Resonance results in louder sounds. ... This is because of the surrounding environment, resonates with the cavity of the shell .

Explanation:

Tpy6a [65]4 years ago

4 0

Question:

What does resonance result in?

A) Quieter sounds B) frequency, C) amplitude D) Louder sounds.

Answer:

Resonance results in louder sounds.

Explanation:

In fact, the point at which the sound show maximum amplitude is termed as resonance. Since there is an increase in amplitude, the sound turns louder, and louder. Resonance is the situation, where one body vibrates after being effected by another vibrating body. Let us take an example of two bodies ‘A’ and ‘B’ at vibration.

Let the body A is in vibration at a particular frequency. And then, let the body ‘B’ disturbs with its vibration. Now, ‘A’ imparts some additional frequency, from ‘B’, which leads to resonance. So, if the amplitude increases, the sound produced is huge, and hence louder.

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A closely wound, circular coil with a diameter of 4.30 cm has 470 turns and carries a current of 0.460 A .

Nadusha1986 [10]

Hi there!

a)
Let's use Biot-Savart's law to derive an expression for the magnetic field produced by ONE loop.

$dB = \frac{\mu_0}{4\pi} \frac{id\vec{l} \times \hat{r}}{r^2}$

dB = Differential Magnetic field element

μ₀ = Permeability of free space (4π × 10⁻⁷ Tm/A)

R = radius of loop (2.15 cm = 0.0215 m)

i = Current in loop (0.460 A)

For a circular coil, the radius vector and the differential length vector are ALWAYS perpendicular. So, for their cross-product, since sin(90) = 1, we can disregard it.

$dB = \frac{\mu_0}{4\pi} \frac{id\vec{l}}{r^2}$

Now, let's write the integral, replacing 'dl' with 'ds' for an arc length:
$B = \int \frac{\mu_0}{4\pi} \frac{ids}{R^2}$

Taking out constants from the integral:
$B =\frac{\mu_0 i}{4\pi R^2} \int ds$

Since we are integrating around an entire circle, we are integrating from 0 to 2π.

$B =\frac{\mu_0 i}{4\pi R^2} \int\limits^{2\pi R}_0 \, ds$

Evaluate:
$B =\frac{\mu_0 i}{4\pi R^2} (2\pi R- 0) = \frac{\mu_0 i}{2R}$

Plugging in our givens to solve for the magnetic field strength of one loop:

$B = \frac{(4\pi *10^{-7}) (0.460)}{2(0.0215)} = 1.3443 \mu T$

Multiply by the number of loops to find the total magnetic field:
$B_T = N B = 0.00631 = \boxed{6.318 mT}$

Now, we have an additional component of the magnetic field. Let's use Biot-Savart's Law again:
$dB = \frac{\mu_0}{4\pi} \frac{id\vec{l} \times \hat{r}}{r^2}$

In this case, we cannot disregard the cross-product. Using the angle between the differential length and radius vector 'θ' (in the diagram), we can represent the cross-product as cosθ. However, this would make integrating difficult. Using a right triangle, we can use the angle formed at the top 'φ', and represent this as sinφ.

$dB = \frac{\mu_0}{4\pi} \frac{id\vec{l} sin\theta}{r^2}$

Using the diagram, if 'z' is the point's height from the center:

$r = \sqrt{z^2 + R^2 }\\\\sin\phi = \frac{R}{\sqrt{z^2 + R^2}}$

Substituting this into our expression:
$dB = \frac{\mu_0}{4\pi} \frac{id\vec{l}}{(\sqrt{z^2 + R^2})^2} }(\frac{R}{\sqrt{z^2 + R^2}})\\\\dB = \frac{\mu_0}{4\pi} \frac{iRd\vec{l}}{(z^2 + R^2)^\frac{3}{2}} }$

Now, the only thing that isn't constant is the differential length (replace with ds). We will integrate along the entire circle again:
$B = \frac{\mu_0 iR}{4\pi (z^2 + R^2)^\frac{3}{2}}} \int\limits^{2\pi R}_0, ds$

Evaluate:
$B = \frac{\mu_0 iR}{4\pi (z^2 + R^2)^\frac{3}{2}}} (2\pi R)\\\\B = \frac{\mu_0 iR^2}{2 (z^2 + R^2)^\frac{3}{2}}}$

Multiplying by the number of loops:
$B_T= \frac{\mu_0 N iR^2}{2 (z^2 + R^2)^\frac{3}{2}}}$

Plug in the given values:
$B_T= \frac{(4\pi *10^{-7}) (470) (0.460)(0.0215)^2}{2 ((0.095)^2 + (0.0215)^2)^\frac{3}{2}}} \\\\ = 0.00006795 = \boxed{67.952 \mu T}$

5 0

2 years ago

Read 2 more answers

________ reaction time involves selecting a specific and correct response from several choices when presented with several diffe

kobusy [5.1K]

Complex reaction time involves selecting a specific and correct response from several choices when presented with several different stimuli.
Answer: A

8 0

4 years ago

Read 2 more answers

6. A 0.09 kg arrow hits a target at 22 m/s and penetrates 4 cm before stopping.

tatyana61 [14]

A ) v = v o - a t
0 = 22 - a · t
a · t = 22
d = v o · t - a t²/2
0.04 = 22 t - 22 t / 2
0.04 = 11 t
t = 0.04 : 11 = 0.003636 s
a = 22 / t
a = 6050 m/s²
F = m · a = 0.09 kg · 6050 m/s²
F ( target→arrow) = - 544.5 N
b ) F ( arrow→target ) = 544.5 N
c ) If the speed was doubled: v = 44 m/s;
F = a m
a = 6050 m/s²
a · t = 44
t = 6050 : 0.04
t = 0.007272 s
d = 44 t - 44 t/2 = 22 t
d = 22 · 0.007272
d = 0.16 m = 16 cm

8 0

3 years ago

Ayuda porfavor! y que sea buena respuesta..

Sav [38]

Answer:

Dencidad = 600 kg/m³

Explanation:

Dados los siguientes datos;

Lado del cubo = 10 cm a metros = 10/100 = 0,1 m

Masa = 0,6 kg

Para encontrar la densidad;

En primer lugar, determinaríamos el volumen del cubo usando la fórmula;

Volumen del cubo = lados³

Volumen del cubo = 0.1³

Volumen del cubo = 0.001 m³

Ahora, podemos encontrar la densidad usando la fórmula;

Dencidad = masa/volumen

Dencidad = 0,6/0,001

Dencidad = 600 kg/m³

8 0

3 years ago

The stroke that begins a point in volleyball is

natka813 [3]

The stroke that begins a point in volleyball is called a serve

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3 years ago