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3 years ago

6. At a school supply store, the price of three

Mathematics

2 answers:

AlexFokin [52]3 years ago

7 0

Answer:

Answer is b

Step-by-step explanation:

x= number of notebooks

AnnZ [28]3 years ago

4 0

<h3>The answer is:</h3><h2>B</h2><h2 />

First, look for some of the key words in the word problem.

Now we can use those key words and translate it into an equation.

You don't know the price of 3 notebooks, so you should put: 3x

Instead of saying plus, we can say: +

It says "...3 notebooks plus a $30 backpack..." so we add 30.

Instead of saying "is the same as the", we can say: =

You don't know the price of 11 notebooks either, so you should put: 11x

Now, put together the equation:

3x + 30 = 11x

There is your equation! Match it up with one of the given answers and you will receive B.

You might be interested in

Use Newton’s method to approximate the indicated root of the equation correct to six decimal places. The positive root of 3 sin

MAXImum [283]

Answer:

$x \approx 2.278863$

Step-by-step explanation:

Required

The positive root of $3\sin(x) = x$

Equate to 0

$0 = x -3\sin(x)$

So, we have our function to be:

$h(x) = x -3\sin(x)$

Differentiate the above function:

$h'(x) = 1 -3\cos(x)$

Using Newton's method of approximation, we have:

$x_{n+1} = x_n - \frac{h(x_n)}{h'(x_n)}$

Plot the graph of $h(x) = x -3\sin(x)$ to get $x_1$ --- see attachment for graph

From the attached graph, the first value of x is at 2.2; so:

$x_1 = 2.2$

So, we have:

$x_{n+1} = x_n - \frac{h(x_n)}{h'(x_n)}$

$x_{1+1} = x_1 - \frac{h(x_1)}{h'(x_1)}$

$x_{2} = 2.2 - \frac{2.2 -3\sin(2.2)}{1 -3\cos(2.2)} = 2.28153641$

The process will be repeated until the digit in the 6th decimal place remains unchanged

$x_{3} = 2.28153641 - \frac{2.28153641 -3\sin(2.28153641)}{1 -3\cos(2.28153641)} = 2.2788654$

$x_{4} = 2.2788654 - \frac{2.2788654 -3\sin(2.2788654)}{1 -3\cos(2.2788654)} = 2.2788627$

$x_{5} = 2.2788627 - \frac{2.2788627-3\sin(2.2788627)}{1 -3\cos(2.2788627)} = 2.2788627$

Hence:

$x \approx 2.278863$

4 0

3 years ago

Teresa, Eric, and Ryan sent a total of 99 text messages over their cell phones during the weekend. Eric sent 3 times as

faust18 [17]

I'll use t for the messages Teresa sent, e for messages Eric sent, and r for messages Ryan sent.

Therefore we have, t+e+r=99.

From the text we also know:

e=3r ; r=t+6

If we substitute in the original equation we get:

t+3(t+6)+t+6=99; By simplifying it we get

5t=75 , therefore t=75/5=15.

Since Teresa send 15 messages,Ryan sent 6 more then here, so he send 21. Eric sent three times the

messages Ryan sent so he sent 63 messages. If we add them together 15+21+63, we get the total of 99 messages.

8 0

3 years ago

Plz help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Harrizon [31]

You at the photos and what you see put it down and what you know put it down

8 0

3 years ago

Al principio Eduardo y Adrián tenían el mismo número de dulces. Eduardo le dio a Adrián la mitad de los dulces que tenía. Despué

Dennis_Churaev [7]

Answer:

Al final, Eduardo tenía 20 dulces.

Step-by-step explanation:

Dado que al principio Eduardo y Adrián tenían el mismo número de dulces, y Eduardo le dio a Adrián la mitad de los dulces que tenía, y después, Adrián le dio a Eduardo la mitad de los dulces que tenía él en ese momento, así que a Adrián le quedaron 12 dulces, para determinar cuántos dulces tenía Eduardo al final se debe realizar el siguiente cálculo:

Eduardo 1X = Adrián 1X

Eduardo 0.5X = Adrián 1.5X

Eduardo 1.25X = Adrián 0.75X

0.75 X = 12

X = 12 / 0.75

X = 16

1.25 X = 16 x 1.25 = 20

Así, al final, Eduardo tenía 20 dulces.

6 0

3 years ago

NEED HELP ASAP!! IF YOU ANSWER RIGHT YOU GET BRAINLIEST!!!!!

lana66690 [7]

Answer:

5x^2 +10x

Step-by-step explanation:

The area is the product of the height and width. For this exercise, it is convenient to compute the rectangle areas individually, then write their sum:

blue rectangle area = (5x)(x) = 5x^2

red rectangle area = (5x)(2) = 10x

Total area = 5x^2 +10x.

_____

If you start by writing an expression for the total area, expanding it requires you deal with the unlike terms separately anyway:

5x(x +2) = 5x(x) +5x(2) = 5x^2 +10x

7 0

3 years ago