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TiliK225 [7]
3 years ago
5

If the solution to y=4x+3 is (4,16) what would the steps needed to get (4,16) be?

Mathematics
1 answer:
Ainat [17]3 years ago
8 0
<span>Simplifying x4 = 16
 Solving x4 = 16
 Solving for variable 'x'.
  Move all terms containing x to the left, all other terms to the right.
Simplifying x4 = 16
 Reorder the terms: -16 + x4 = 16 + -16
 Combine like terms: 16 + -16 = 0 -16 + x4 = 0
 Factor a difference between two squares. (4 + x2)(-4 + x2) = 0
 Factor a difference between two squares. (4 + x2)((2 + x)(-2 + x)) = 0
Subproblem 1

Set the factor '(4 + x2)' equal to zero and attempt to solve:
 Simplifying 4 + x2 = 0 Solving 4 + x2 = 0
 Move all terms containing x to the left, all other terms to the right.
 Add '-4' to each side of the equation. 4 + -4 + x2 = 0 + -4
 Combine like terms: 4 + -4 = 0 0 + x2 = 0 + -4 x2 = 0 + -4
 Combine like terms: 0 + -4 = -4 x2 = -4
 Simplifying x2 = -4
The solution to this equation could not be determined.
 This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(2 + x)' equal to zero and attempt to solve:
 Simplifying 2 + x = 0 Solving 2 + x = 0
 Move all terms containing x to the left, all other terms to the right.
 Add '-2' to each side of the equation. 2 + -2 + x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + x = 0 + -2 x = 0 + -2
 Combine like terms: 0 + -2 = -2 x = -2 Simplifying x = -2

Sub-problem 3

Set the factor '(-2 + x)' equal to zero and attempt to solve:
 Simplifying -2 + x = 0 Solving -2 + x = 0
 Move all terms containing x to the left, all other terms to the right.
 Add '2' to each side of the equation. -2 + 2 + x = 0 + 2
 Combine like terms: -2 + 2 = 0 0 + x = 0 + 2 x = 0 + 2
 Combine like terms: 0 + 2 = 2 x = 2 Simplifying x = 2Solutionx = {-2, 2}</span>
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Mazyrski [523]

Just to be different we'll start with intercept intercept form which says the line through x intercept (a,0) and y intercept (0,b) is

\dfrac x a + \dfrac y b = 1

Through (4,0) and (0,-2) that's

\dfrac{x}{4} + \dfrac{y}{-2} = 1

Multiply through by the common denominator of 4 for standard form:

x - 2y = 4

For slope intercept form we solve for y

-2 y = -x + 4

y = (1/2) x - 2

We see our slope is (1/2) and we go through (4,0) so point slope form is

y - 0 = (1/2)(x - 4)

y = (1/2)(x-4)

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3 years ago
Which is parallel to y = 3x − 5?
nikklg [1K]
The answer is y=3x-6!!!!!
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3 years ago
(Please 75 points if answerd need this is 1 min)
chubhunter [2.5K]

Answer:

(5,-4)

Step-by-step explanation:

If reflected over the x-axis, the quadrilateral would be in the fourth quadrant. N' would be at (1,-1) and P' at (6,-1). To reflect, look at the y-coordinate of the point and turn it to negative. With point Q, it's at (5,4) so we just flip the 4 to -4 and that's our point! (5,-4)

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Divide 5/9 round to the nearest tenth
zhenek [66]

Answer:

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Step-by-step explanation:

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3 0
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Read 2 more answers
What is the expression in radical form?<br><br> (4x3y2)310
sertanlavr [38]

Given:

Consider the given expression is

(4x^3y^2)^{\frac{3}{10}}

To find:

The radical form of given expression.

Solution:

We have,

(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}

(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}

(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}

(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}       [\because x^{\frac{1}{n}}=\sqrt[n]{x}]

(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}       [\because x^{\frac{1}{n}}=\sqrt[n]{x}]

Therefore, the required radical form is \sqrt[5]{8y^3}\sqrt[10]{x^9}.

8 0
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