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TiliK225 [7]
3 years ago
5

If the solution to y=4x+3 is (4,16) what would the steps needed to get (4,16) be?

Mathematics
1 answer:
Ainat [17]3 years ago
8 0
<span>Simplifying x4 = 16
 Solving x4 = 16
 Solving for variable 'x'.
  Move all terms containing x to the left, all other terms to the right.
Simplifying x4 = 16
 Reorder the terms: -16 + x4 = 16 + -16
 Combine like terms: 16 + -16 = 0 -16 + x4 = 0
 Factor a difference between two squares. (4 + x2)(-4 + x2) = 0
 Factor a difference between two squares. (4 + x2)((2 + x)(-2 + x)) = 0
Subproblem 1

Set the factor '(4 + x2)' equal to zero and attempt to solve:
 Simplifying 4 + x2 = 0 Solving 4 + x2 = 0
 Move all terms containing x to the left, all other terms to the right.
 Add '-4' to each side of the equation. 4 + -4 + x2 = 0 + -4
 Combine like terms: 4 + -4 = 0 0 + x2 = 0 + -4 x2 = 0 + -4
 Combine like terms: 0 + -4 = -4 x2 = -4
 Simplifying x2 = -4
The solution to this equation could not be determined.
 This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(2 + x)' equal to zero and attempt to solve:
 Simplifying 2 + x = 0 Solving 2 + x = 0
 Move all terms containing x to the left, all other terms to the right.
 Add '-2' to each side of the equation. 2 + -2 + x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + x = 0 + -2 x = 0 + -2
 Combine like terms: 0 + -2 = -2 x = -2 Simplifying x = -2

Sub-problem 3

Set the factor '(-2 + x)' equal to zero and attempt to solve:
 Simplifying -2 + x = 0 Solving -2 + x = 0
 Move all terms containing x to the left, all other terms to the right.
 Add '2' to each side of the equation. -2 + 2 + x = 0 + 2
 Combine like terms: -2 + 2 = 0 0 + x = 0 + 2 x = 0 + 2
 Combine like terms: 0 + 2 = 2 x = 2 Simplifying x = 2Solutionx = {-2, 2}</span>
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Equation at the end of step  1  :

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√ 96   =  √ 2•2•2•2•2•3   =2•2•√ 6   =

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The equation has two real solutions  

These solutions are  r = 4 • ± √6 = ± 9.7980  

Two solutions were found :

                  r = 4 • ± √6 = ± 9.7980

Processing ends successfully

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