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3 years ago

A student wishes to increase an amount by 10% and then by 30%. What is the single multiplier that can be used?

Mathematics

1 answer:

liraira [26]3 years ago

7 0

Step-by-step explanation:

let an amount be a

increase an amount by 10% and then by 30%

= a*1.1 *1.3 = a*1.43

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Mark makes $60 for every six hour shift he works. How much will he make if he works an eight hour shift

Illusion [34]

Answer:

Mark will make $80 if he works an eight-hour shift.

Step-by-step explanation:

For every six hour shift he works, Mark makes $60

This implies that for every hour, he makes $10 ($60/6)

Therefore, for working an eight-hour shift, Mark will make $80 ($10 * 8) or ($60/6 * 8).

We can conclude that Mark's employer pays him $10 per hour.

This hourly rate can be used to work out how much Mark will earn if he works for a month or a year, as the case may be.

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2 years ago

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TiliK225 [7]

Answer:-23

Step-by-step explanation:

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2 years ago

A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex

Olenka [21]

Answer:

The 90% confidence interval that estimate the true proportion of students who receive financial aid is

$0.533 < p < 0.64$

$n = 1789$

Step-by-step explanation:

Considering question a

From the question we are told that

The sample size is n = 200

The number of student that receives financial aid is $k = 118$

Generally the sample proportion is

$\^ p = \frac{k}{n}$

=> $\^ p = \frac{118}{200}$

=> $\^ p = 0.59$

From the question we are told the confidence level is 90% , hence the level of significance is

$\alpha = (100 - 90 ) \%$

=> $\alpha = 0.10$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }$

=> $E = 1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }$

=> $E = 0.057$

Generally 90% confidence interval is mathematically represented as

$\^ p -E < p < \^ p +E$

=> $0.533 < p < 0.64$

Considering question b

From the question we are told that

The margin of error is E = 0.03

From the question we are told the confidence level is 99% , hence the level of significance is

$\alpha = (100 - 99 ) \%$

=> $\alpha = 0.01$

Generally from the normal distribution table the critical value of is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the sample size is mathematically represented as

$[\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )$

=> $n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )$

=> $n = 1789$

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3 years ago

I am so stuck plz help me simplify these

pishuonlain [190]

Answer:

2b + 3c

3d + 2e

14b

10d + 21e

7m + 14n

12p + 18q

13a + 11b + 10c

4 0

3 years ago

Read 2 more answers

which expression is equivalent to (^3sqrtm)^7 in exponential form? a) 7 m/3 b) 3 m/7 c) m 3/7 d) m 7/3

Komok [63]

$(\sqrt[3]{m})^{7} = m^{ \frac{7}{3}}$

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2 years ago