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2 years ago

Pierce swims 10 laps in a pool in 8 minutes. He spent the same amount of time on each lap. How much time did each lap take him?

Mathematics

1 answer:

Novosadov [1.4K]2 years ago

8 0

Answer:

Each lap took him 48 seconds

Step-by-step explanation:

Pierce swims 10 laps in 8 minutes.

Let the amount of time he spent for each lap = t minutes.

Then, since each lap takes equal time, the total time taken for 10 laps = 10t minutes.

But, it is given that the total time taken for 10 laps = 8 minutes.

Therefore,

10t = 8

Divide both sides by 10.

t = 0.8 minutes or

t = 48 seconds

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What is the slope of the line that passes through the points (-2, 7) and (2,-5)?

Deffense [45]

Answer:

Denote that line: y = ax + b

Line passes (-2, 7) and (2,-5):

=> -2a + b =7

=> 2a + b = -5

Add both side of above equations:

=> 2b = 2

=> b = 1

=> a = (-5 - 1)/2 = -3

=> Slope a = -3

Hope this helps!

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2 years ago

Matthew deposits $400 into an account that earns 7% interest compounded quarterly. What is the balance in his account after 10 y

user100 [1]

Answer:

$787

Step-by-step explanation:

In terms of interest

To find the multiplier using '7% more' continues as follows

100% + 7% = 107%

107/100 = 1.07 (multiplier)

Add the ten years as a power to the multiplier

1.07^10

And multiply this by $400

400 x 1.07^10 = 786.860542916

To the nearest dollar = $787

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2 years ago

Read 2 more answers

What is the factored form of 27d^6+8g^12

likoan [24]

Answer:

The second one is the best answer to your question

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2 years ago

Which side lengths form a right triangle?<br> Choose all answers that apply:

kkurt [141]

Answer:

All 3 are right triangles.

Step-by-step explanation:

In a right triangle c^2 = a^2 + b^2 where c is the longest side. ( by Pythagoras).

a) 3^2 = 9, 6^2 = 36 and √27 ^ 2 = 27

36 = 9 + 27

So this is a right triangle.

17^2 = 289, 15^2 = 225 and 8^2 = 64

289 = 225 + 64

Also right triangle.

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1 year ago

Which is the value of this expression when p=-2 and q=-1?

saul85 [17]

Answer:

D. 4

Step-by-step explanation:

$[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4$

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2 years ago