Question

Suppose a bag of marbles has 4 green, 2 red, 5 yellow, 1 brown, and 7 blue marbles. What is the probability of picking a green marble?

Answer 1

The bag of marbles has 4 green, 2 red, 5 yellow, 1 brown, and 7 blue marbles.

Total number of marble=4+2+5+1+7=19

The probability P(E) is defined as $P(E)=\frac{n(E)}{n(s)}$

where n(E) is the total number of favourable events.

and n(s) is the total number of events

Hence for the given data we can write

$P(E)=\frac{4}{19}$

Because total number of green marbles = n(E)=4

Total number of Marbles =n(S)=19

Hence P(E)=4/19

Answer 2

Total number of marbles =19
=>(probability of getting a green marble)=number if green marbles/total number of marbles
=>4/19
Hope this helps.....