The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
<h3>What is the radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.?</h3>
Generally, the equation for side lengths AB is mathematically given as
Triangle ABC has side lengths
Where
- AB = 65,
- BC = 33,
- AC = 56.
Hence
r √ 2 · (89 √ 2/2 − r √ 2) = r(89 − 2r),
r = 89 − 65
r= 24.
In conclusion, The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
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Answer:
$1.30
Step-by-step explanation:
Let x = the cost of the pencil
Let x + .80 = the cost of the pen
Let 4(x + .80) = the cost of the binder
x + x + .80 + 4(x + .80) = 11.80
2x + .80 + 4x + 3.20 = 11.80
6x + 4.00 = 11.80
6x = 7.80
x = $1.30
x + .80 = $2.10
4(x + .80) = $8.40
Answer:
B
Step-by-step explanation:
P(AUB)=P(A)+P(B)-P(A∩B)
191/400=7/20+P(B)-49/400
P(B)=191/400+49/400-7/20=240/400-7/20=12/20-7/20=5/20=1/4
Answer: B.) 3/4
Step-by-step explanation:
I Got B by dividing 7 by 21 and 28 which is 3 and 4 so B is the correct answer.
Here, x - 2y = 14
x = 14 + 2y
Now, substitute this value into first equation,
4x + 6y = 0
4(14 + 2y) + 6y = 0
56 + 8y + 6y = 0
14y = -56
y = -56/14
y = -4
Substitute it into second equation,
x = 14 + 2(-4)
x = 14 - 8
x = 6
In short, Your Answer would be: (6, -4)
Hope this helps!
