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3 years ago

We classify muddy water as a suspension because the particles of mud

1 answer:

4 0

The particles of mud don't actually mix with the water and are still the same molecule. As compared to a solution which is a new chemical compound, mud is just dirt and water.

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Starting with acetylene and bromoethane, show how you would use reagents from the table to synthesize 3-hexanone.

Jobisdone [24]

solution:

A = 192 x (1/2) ^ (15/5) = 192 x (1/2) ^3 = 192 x 1/8 = 24 mg

Starting by hitting acetylene with NaNH2 to deprotonate, this C-- will attack the C connected to the Br Sn2 style to lengthen the chain by two carbons.

Do this same thing again with the other CH of the acetylene and another bromoethaneto get a six carbon chain, namely, 3-hexyne.

Now, reduce the alkyne to an alkene via H2/Pd/C, and that gives 3-hexene.

3 0

3 years ago

The pyrolysis of ethane proceeds with an activation energy of about 300 kJ/mol. How much faster is the decomposition at 625°C th

Alona [7]

Answer:

The decomposition of ethane is 153.344 times much faster at 625°C than at 525°C.

Explanation:

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_2$ = rate of reaction at $T_2$

$K_1$ = rate of reaction at $T_1$

$Ea$ = activation energy of the reaction

R = gas constant = 8.314 J/K mol

$E_a=300 kJ/mol=300,000 J/mol$

$T_2=625^oC=898.15 K,T_1=525^oC=798.15 K$

$\log (\frac{K_2}{K_1})=\frac{300,000 J/mol}{2.303\times 8.314 J/K mol}[\frac{1}{798.15 K}-\frac{1}{898.15 K}]$

$\log (\frac{K_2}{K_1})=2.185666$

$K_2=153.344\times K_1$

The decomposition of ethane is 153.344 times much faster at 625°C than at 525°C.

4 0

3 years ago

A sample of 10.5 g of nitrogen reacts with 20.2 g of hydrogen to produce ammonia. (36 points

BartSMP [9]

Answer:

Explanation:

A. 55

B. 43

C. 14

D. 29

6 0

2 years ago

The lower the ph of a solution, the ______.

gtnhenbr [62]

B

a and c are unrelated
d: ph will increase

3 0

4 years ago

Read 2 more answers

Chlorine can bond with fluorine to form CIF. Chlorine can also bond with lithium to form LiCI Which compound will have a greater

Sergio [31]

Answer: $ClF$ will have a greater partial charge.

Explanation:

A polar covalent bond is defined as the bond which is formed when there is a low difference of electronegativities between the atoms, thus resulting in charge difference. Example: $ClF$

Non-polar covalent bond is defined as the bond which is formed when there is no difference of electronegativities between the atoms and thus there is no charge difference. Example: $F_2$

Ionic bond is formed when there is complete transfer of electron from a highly electropositive metal to a highly electronegative non metal. The electronegative difference between the elements is high. The charges on cation and anion neutralise each other. Example: $LiCl$

Thus as $ClF$ will have greater partial charge.

5 0

4 years ago