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3 years ago

12

The study of how humans impact the environment is ?

2 answers:

lesya692 [45]3 years ago

5 0

Answer:

Anthropocene

Explanation:

The atmospheric scientist Paul Crutzen introduced the term "Anthropocene" in the mid-1970s. The term is sometimes used in the context of pollution emissions that are produced from human activity since the start of the Agricultural Revolution but also applies broadly to all major human impacts on the environment.

Ber [7]3 years ago

3 0

<em><u>Humans impact the physical environment in many ways: overpopulation, pollution, burning fossil fuels, and deforestation. </u></em>

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After reading the list of physical properties above, you realize that they are describing a substance that is a

Alecsey [184]

The answer is B

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3 years ago

Question 14 A student dissolves 1.5g of styrene C8H8 in 225.mL of a solvent with a density of 1.02/gmL . The student notices tha

Yuki888 [10]

We must to know:

Cm = molarity = niu / Vs, when the niu = no. of moles and Vs = Volume of solution

the no. niu = mass / molecular mass of substance

molecular mass of C8H8 = 12x8+8x1 = 104 g/mol

=> niu = 1,5 / 104 = 0,0144 moles C8H8

=> Cm = 0,0144/0,225 = 0,06 mol/L

Cmm = molality = niu (C8H8) / mass of solvent (kg)

=> p = mass / V => mass (solvent) = p x V

=> 225 x 1,02 = 229,5 g solvent = 0,2295 kg solvent

=> Cmm = 0,0144 / 0,229,5 = 0,063

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In a neutralization reaction, 24.6 mL of 0.300 M H2SO4(aq) reacts completely with 20.0 mL of NaOH(aq). The products are Na2SO4(a

stiv31 [10]

Answer : The concentration of the NaOH solution is, 0.738 M

Explanation :

To calculate the concentration of base, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=0.300M\\V_1=24.6mL\\n_2=1\\M_2=?\\V_2=20.0mL$

Putting values in above equation, we get:

$2\times 0.300M\times 24.6mL=1\times M_2\times 20.0mL$

$M_2=0.738M$

Thus, the concentration of the NaOH solution is, 0.738 M

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3 years ago