The simplest ratios compare only two values, but ratios comparing three or more values are also possible. In any situations in which two or more distinct numbers or quantities are being compared, ratios are applicable. By describing quantities in relation to each other, they explain how chemical formulas can be duplicated or recipes in the kitchen expanded.
Please let me know if I’m wrong
Answer:
10.5 g
Explanation:
Step 1: Given data
- Molar concentration of the solution (C): 0.243 M
- Volume of solution (V): 0.580 L
Step 2: Calculate the moles of solute (n)
Molarity is equal to the moles of solute divided by the liters of solution.
M = n/V
n = M × V
n = 0.243 mol/L × 0.580 L = 0.141 mol
Step 3: Calculate the mass corresponding to 0.141 moles of KCl
The molar mass of KCl is 74.55 g/mol.
0.141 mol × 74.55 g/mol = 10.5 g
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The question is incomplete, complete question is:
A solution containing CaCl2 is mixed with a solution of Li2C2O4 to form a solution that is in calcium ion and in oxalate ion. What will happen once these solutions are mixed?
Answer:
On mixing of both the solutions no precipitation will occur due to lower value of an ionic product of calcium oxalate from its solubility product.
Explanation:
Molar concentration of calcium ions =
Molar concentration of oxalate ions =
ionic product of calcium oxalate in solution :
Solubility product of calcium oxalate =
Generally precipitation occurs when ionic product of substance in solution exceeds its solubility product.
(precipitation occurs)
(non precipitation occurs)
On mixing of both the solutions no precipitation will occur due to lower value of an ionic product of calcium oxalate from its solubility product.