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LenKa [72]
3 years ago
13

How much heat is required to raise the temperature of 670g of water from 25.7"C to 66,0°C? The specific heat

Chemistry
1 answer:
inna [77]3 years ago
8 0

Answer:

Explanation:

q= mc theta

where,

Q = heat gained

m = mass of the substance = 670g

c = heat capacity of water= 4.1 J/g°C    

theta =Change in temperature=( 66-25.7)

Now put all the given values in the above formula, we get the amount of heat needed.

q= mctheta

q=670*4.1*(66-25.7)

  =670*4.1*40.3

=110704.1

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Predict the products of the reaction below
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Answer:

HNO₃ + NaOH ---> NaNO₃ + H₂O

Explanation:

This reaction appears to be a double-displacement reaction. In these reaction, the cation of one compound is swapped with the cation of another.

As such, the hydrogen cation (H⁺) from HNO₃ is swapped with the sodium cation (Na⁺) of NaOH.

Luckily, all of the cations have a +1 charge and the anions have a -1 charge. This means that no coefficients are necessary to balance the reaction.

The <u>complete balanced </u>equation is:

HNO₃ + NaOH ---> NaNO₃ + H₂O

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Questions 18-20 refer to the reaction 2NH3 (g) ↔ N2 (g) + 3H2 (g), and ΔH = 92.2 kJ.
Fittoniya [83]
18. <span>Answer is </span>A

<span>  
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<span>
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19. Answer is A.

The reactant side has 2 moles/molecules of reactants and the product side has 4 moles/molecules of products which come from 1 N₂(g) and 3 H₂<span>(g). If the pressure is reduced in the system, according to the Le Chatelier's principle, the system tries to increase the pressure. </span><span>Hence, forward reaction is promoted because of the higher number of molecules in product side. If the forward reaction is promoted, the concentration of NH</span>₃(g) will decreased.


<span>20. </span>Answer is C.

If the concentration of reactant is increased in the system, according to the Le Chatelier's principle, the system tries to reduce the concentration of that reactant. So if NH₃(g) concentration is increased, then to be equilibrium, the forward reaction will be promoted. Then the concentration of N₂<span>(g) will increase.</span>

<span> </span>

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The reaction is shown in the image.


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