How much heat is required to raise the temperature of 670g of water from 25.7"C to 66,0°C? The specific heat
1 answer:
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Answer:
29.2 L
Explanation:
Given data
- Moles (n): 1 mol
- Pressure (P): 0.824 atm
- Temperature (T): 293 K
We can find the volume of the gas (V) of the using the ideal gas equation.
P × V = n × R × T
V = n × R × T / P
V = 1 mol × (0.0821 atm.L/mol.K) × 293 K / 0.824 atm
V = 29.2 L
Answer:
The pH of the final solution is 7.15
Explanation:
50 mL of 2.0 M of and 25 mL of 2.0 M of
were mixed to make a solution
Final volume of the solution after dilution = 200 mL
Final concentration of
Final concentration of
We use Hasselbach- Henderson equation:
Substituting the values:
Therfore, the pH of the final solution is 7.15