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tekilochka [14]
3 years ago
7

Which of the following could be the equation for a parabola that opens to the left with vertex (5,-12)?

Mathematics
2 answers:
Levart [38]3 years ago
7 0
B. is the answer!

Hope this helps!

HACTEHA [7]3 years ago
3 0

Answer:

The correct option is C) x=-(y+12)^2+5.    

Step-by-step explanation:

Consider the provided information.

The equation of a parabola (horizontal) is:

x=a(y-k)^2+h

Where (<em>h</em>,<em>k</em>) are the vertex of the parabola.

Parabola opens left if the value of <em>a</em> is negative.

It is given that the vertex of the parabola is (5,-12) and it opens to the left.

Substitute the value of <em>a</em> = -1, <em>h</em> = 5 and <em>k</em> = -12 in the equation of parabola.

x=-1(y-(-12))^2+5

x=-(y+12)^2+5

For better understanding refer to the figure 1:

Therefore, the correct option is C) x=-(y+12)^2+5.

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