Question

Which of the following could be the equation for a parabola that opens to the left with vertex (5,-12)?

Answer 1

B. is the answer!

Hope this helps!

Answer 2

Answer:

The correct option is C) $x=-(y+12)^2+5$.    

Step-by-step explanation:

Consider the provided information.

The equation of a parabola (horizontal) is:

$x=a(y-k)^2+h$

Where (h,k) are the vertex of the parabola.

Parabola opens left if the value of a is negative.

It is given that the vertex of the parabola is (5,-12) and it opens to the left.

Substitute the value of a = -1, h = 5 and k = -12 in the equation of parabola.

$x=-1(y-(-12))^2+5$

$x=-(y+12)^2+5$

For better understanding refer to the figure 1:

Therefore, the correct option is C) $x=-(y+12)^2+5$.