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In-s [12.5K]
2 years ago
5

Determine if the following system of equations has no solutions, infinitely many

Mathematics
1 answer:
mylen [45]2 years ago
8 0
This are similar answers to your questions.

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Given: j(x) = x2 - 2x + 1
kicyunya [14]

Answer:

{1, 0, 16}

Step-by-step explanation:

given..

j(x) = x^2-2x+1

put all given values of domain (1,0 and 5 ) in the equation..

the values you get are range of the function

4 0
3 years ago
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Raul ate 7/8 of 1/2 a pizza. How much of the pizza did Raul eat?
3241004551 [841]

Answer:

<u>7</u>

16

Step-by-step explanation:

7/8× 1/2=

<u>7 × 1</u><u> </u>

8 × 2

=7/16

5 0
2 years ago
The lines below are parallel. If the slope of the green line is -3, what is the
siniylev [52]

Answer:

m=-3

Step-by-step explanation:

Since the lines are parallel to each other, their gradients are equal.

∴ gradient of green line = gradient of red line

∴ m = -3

6 0
2 years ago
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A kite is a quadrilateral with two pairs of adjacent, congruent sides. The vertex angles are those angles in between the pairs o
umka21 [38]

Let the kite is the quadrilateral A B C D with the two pairs of adjacent congruent sides. (Please find the attached diagram also) 

Now, its given in question, see from figure,

AB is congruent to AD 

BC is congruent to DC 

So, let us join the points A & C to form AC ; and points B and D to form BD. 

So, AC is common side  to triangles ABC and ADC. 

So, Because AB ≈AD

BC ≈ DC

And, AC is common, therefore, 

triangle ABC is congruent to triangle ADC 

⇒∠ ABC ≈ ∠ADC

The above are the angle.

4 0
3 years ago
The complex zeros of the following polynomial function. Write f in factored form.
zavuch27 [327]

Answer:  \bold{x=-3\qquad x=\dfrac{3+3i\sqrt3}{2}\qquad x=\dfrac{3-3i\sqrt3}{2}}

<u>Step-by-step explanation:</u>

The formula for factoring a cubic is:

a³ + b³ = (a + b)(a² - ab + b²)

f(x) = x³ + 3³

     = (x + 3)(x² - 3x + 9)

To find the zeros, set each factor equal to zero and solve.

0 = x + 3      0 = x² - 3x + 9

-3 = x                use quadratic formula

x^2-3x+9\quad \rightarrow \quad a=1, b=-3, c=9\\\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-3)\pm\sqrt{(-3)^2-4(1)(9)}}{2(1)}\\\\\\x=\dfrac{3\pm\sqrt{9-36}}{2}\\\\\\x=\dfrac{3\pm\sqrt{-27}}{2}\\\\\\x=\dfrac{3\pm3i\sqrt{3}}{2}

Answer:

x=-3\qquad x=\dfrac{3+3i\sqrt3}{2}\qquad x=\dfrac{3-3i\sqrt3}{2}

7 0
3 years ago
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