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Helga [31]
3 years ago
15

Kate paid $27 for a dress that was on sale at 10% off. What was the original price for this dress?

Mathematics
2 answers:
Talja [164]3 years ago
8 0

The original price of the dress was $30. Hope this helps!

wolverine [178]3 years ago
4 0
Hope u understand...

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Darren has a wooden board that is Three-fifths of a meter long. He cuts the board into 3 equal parts. How long is each section o
Alik [6]

Answer:

Each section of the board is 1/3 or 0.334(0.333333333333) of a meter

Step-by-step explanation:

3/5 divided by 3 is the equation we have to do.

3/5 divided by 3 is also equal to 3/5 times the reciprocal of 3 or 1/3

3/5 * 1/3

3*1 = 3

5*3 = 15

3/15 which can simplify to 1/3. (divide numerator and denominator by 3.)

Each section of the board is 1/3 or 0.334(0.333333333333) of a meter

8 0
3 years ago
(-2)(4) - 7^2 help me
wlad13 [49]

Answer:

(-2)(4) - 7^2

-8-7^2

-8-49

=-57

Step-by-step explanation:

4 0
3 years ago
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A bucket has 16 inches of water in it but there is a hole in the bottom. Use interval notation to write the domain and range of
Dennis_Churaev [7]

Answer: range:  {0in, 16in}

               domain {0min, 12.8 min}

Step-by-step explanation:

When we have a function:

f(x) = y.

The range is the set of possible values of y and the domain is the set of all the possible values of x.

In this case, our function is:

H(x) = 16 - 1.25*x

which is a linear equation, and we know that the linear equations are defined (for range and domain) in the set of all the real numbers, but this is a physical situation, so we must see at the real problem.

The bucket can not have more water than the initial amount, 16 inches, so this is the maximum in the range.

The minimum height of water that we can find in the bucket is 0 inches (so the bucket is empty) then this is the minimum of the range.

Then we can write the range as:

R: 0in ≤ y ≤ 16in. = {0in, 16in}

Now we can find the extremes of the domain by using the extremes of the range:

y = 16 = 16 - 1.25*x

       0 = -1.25*x

then we have x = 0min, this will be the minimum of the domain.

Now using the minimum of the range y = 0 we have:

y  = 0 = 16 - 1.25*x

      1.25*x = 16

            x  = 16/1.25 = 12.8 mins

This is the maximum time in the domain (because after this time, there is no water in the bucket)

Then the domain is:

D: 0min ≤ x ≤ 12.8 min

5 0
3 years ago
A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th
OlgaM077 [116]

Answer:

Interval [16.34 , 21.43]

Step-by-step explanation:

First step. <u>Calculate the mean</u>

\bar X=\frac{(23+18+23+12+13+23)}{6}=18.666

Second step. <u>Calculate the standard deviation</u>

\sigma =\sqrt{\frac{(23-18.666)^2+(18-18.666)^2+(23-18.666)^2+(12-18.666)^2+(13-18.666)^2+(23-18.666)^2}{6}}

\sigma=\sqrt\frac{18.783+0.443+18.783+44.435+5.666+18.783}{6}

\sigma=\sqrt{17.815}=4.22

As the number of data is less than 30, we must use the t-table to find the interval of confidence.

We have 6 observations, our level of confidence DF is then 6-1=5 and we want our area A to be 80% (0.08).  

We must then choose t = 1.476 (see attachment)

Now, we use the formula that gives us the end points of the required interval

\bar X \pm t\frac{\sigma}{\sqrt n}

where n is the number of observations.

The extremes of the interval are then, rounded to the nearest hundreth, 16.34 and 21.43

6 0
3 years ago
There are 12 boys and 8 girls in a class.
Serga [27]

Answer:12:10

Step-by-step explanation:

6 0
3 years ago
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