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3 years ago

If x = 1 and y = 2 and z = 3 what is 10x³z²- 5x²y³/xyz²

Mathematics

2 answers:

Sholpan [36]3 years ago

8 0

Answer:

so many numbers and letters

Step-by-step explanation:

Taya2010 [7]3 years ago

6 0

Answer:

25/9

Step-by-step explanation:

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In June 2012, Twitter was reporting 400 million tweets per day. Each tweet can consist of up to 140 characters (letter, numbers,

gulaghasi [49]

Each tweet would cost between 1 and 140 pennies you can write that as an inequality [1 ≤ x ≤ 140] Since you can't tweet 0 characters or above 140.

if you want to change it to pounds divide by 100.

A) 1 ≤ x ≤ 140

B) Each character costs a penny, you can't tweet less than 1 character or above 140.

3 0

3 years ago

Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of

IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if n = 100.

(2) A Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable X following a Binomial distribution with parameters n and p.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.10=1$

Thus, a Normal approximation to binomial can be applied for population 1, if n = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

8 0

3 years ago

Which rectangle has a length-to-height ratio of 5:3?

Mamont248 [21]

1.7. 0.8 .89.36 28.28wow

4 0

3 years ago

Evaluate (ab)^2 for a=4 and b=3. A. 81 B. 144 C. 24 D. 36

worty [1.4K]

Substitute the number for the appropriate variables and solve
(ab)^2
(4×3)^2
(12)^2
12×12
144
Your answer is B.144

8 0

3 years ago

...............what is (9x^2-3)^6

Lelu [443]

Step 1. Factor out the common term $3$

$(3(3 x^{2}-1)^{6}$

Step 2. Use Multiplication Distributive Property: $(xy)^{a} = x^{a} y^{a}$

 $3^{6}(3 x^{2}-1)^{6}$

Step 3. Simplify $3^{6}$ to $729$

$729(3 x^{2}-1)^{6}$

Done!

8 0

3 years ago