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Alja [10]
2 years ago
10

What are the coordinates of the circumcenter of this triangle

Mathematics
1 answer:
denis23 [38]2 years ago
5 0

Answer:

We can find circumcenter by using the circumcenter of a triangle formula, where the location of the circumcenter is O(x,y) and the coordinates of a triangle are given as A(x1,y1),B(x2,y2) and C(x3,y3) A ( x 1 , y 1 ) , B ( x 2 , y 2 ) a n d C ( x 3 , y 3 ) .

Step-by-step explanation:

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Find the total due for the following items plus a 15% tip
EleoNora [17]

Answer:

the total due including tip is 55.20

8 0
2 years ago
Read 2 more answers
I need help!! On this question please hurry
hichkok12 [17]

Step-by-step explanation:

<u>Given</u><u>:</u>

Central Enlargement.

AC=4

AB=5

BC=3

Opp=3

Hyp=5

<u>Required</u><u>:</u>

Sin<A

<u>Formula</u><u>:</u>

Sin<A=Opp/hyp

<u>Solution</u><u>:</u>

Sin<A=Opp/Hyp

Sin<A=3/5 or 0.6

5 0
3 years ago
In the diagram shown overline AD and intersect at point E. overline AB and overline CD are parallel . Given the segment length s
Harrizon [31]

Answer:

11.25

Step-by-step explanation:

Since AB and CD  are parallel, ∠D is congruent to ∠A and ∠C is congruent to ∠B.  Therefore the two triangles are similar by the AA postulate.  Now, the corresponding sides are in proportion

Since AE ↔ DE and AB ↔ CD

So, AE/CD = AB/CD

AE/5 = 9/4

AE = 9(5)/4

     = 45/4  = 11.25

8 0
2 years ago
Question 3 (2 marks)
Sav [38]

Answer:

$3385 per week

Step-by-step explanation:

so, he gets $370 plus 4.5% of what he is selling.

$67000 = 100% of selling

1% = 100%/100 = 67000/100 = $670

4.5% = 1% × 4.5 = 670 × 4.5 = $3015

so, he gets $370 + $3015 = $3385 per week

7 0
2 years ago
Isotope mass (amu) abundance (%) 1 203.97304 1.390 2 205.97447 24.11 3 206.97590 22.09 4 207.97665 52.41 find the atomic mass of
Nata [24]
Answer:
average atomic mass = 207.2172085 amu

Explanation:
To get the average atomic mass of an element using the abundance of its isotopes, all you have to do is multiply each isotope by its percentage of abundance and then sum up all the products.

For the question, we have:
203.97304 amu has an abundance of <span>1.390% (0.0139)
</span>205.97447 amu has an abundance of 24.11% (0.2411)
206.97590 amu has an abundance of 22.09% (0.2209)
207.97665 amu has an abundance of 52.41 % (0.5241)

The average atomic mass can be calculated as follows:
average atomic mass = 203.97304(0.0139) + 205.97447(0.2411)
                                     + 206.97590(0.2209) + 207.97665(0.5241)
average atomic mass = 207.2172085 amu

Hope this helps :)
7 0
3 years ago
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