Answer:
Explanation:
Hello,
In this case, since the density is defined as the ratio between the mass and the volume as shown below:
We can compute the density of water for the given 43 g that occupy the volume of 43 mL:
Regards.
Answer is: B₂O₃ + Mg → B + MgO.
B₂O₃ + 3Mg → 2B + 3MgO, balanced.
B₂O₃ - diboron trioxide. White, glassy solid compound.
B - boron. Metalloid, crystalline boron is and amorphous<span> boron is a brown powder.
Mg - magnesium. S</span><span>hiny, gray and solid metal.
MgO - magnesium oxide. W</span><span>hite, </span>hygroscopic<span> solid powder.</span>
The origin is what makes it change
Answer:
Empirical Formula = C₁H₄ or CH₄
Explanation:
Data Given:
Mass of C = 12.0 g
Mass of H = 4 g
Step 1: <u>Calculate Moles of each Element;</u>
Moles of C = Mass of C ÷ At.Mass of C
Moles of C = 12.0 ÷ 12.0
Moles of C = 1.0 mol
Moles of H = Mass of H ÷ At.Mass of H
Moles of H = 4.0 ÷ 1.0
Moles of H = 4.0 mol
Moles of O = %O ÷ At.Mass of O
Moles of O = 53.924 ÷ 16.0
Moles of O = 3.370 mol
Step 2: <u>Find out mole ratio and simplify it;</u>
C H
1.0 4.0
1.0/1.0 4.0/1.0
1 4
Hence,
Empirical Formula = C₁H₄ or CH₄
